如何使用Java中的lambda表达式来实现ObjIntConsumer接口?
ObjIntConsumer接口是一种函数接口,定义在java.util.package包中。此函数接口期望一个对象值和一个int值作为输入,并且不产生任何输出。它仅包含一个函数方法,accept(对象,int)。
语法
@FunctionalInterface
public interface ObjIntConsumer {
void accept(T t, int value)
}在以下示例中,我们可以使用lambda表达式来实现ObjIntConsumer接口。
示例 1
import java.util.function.*;
public class ObjIntConsumerInterfaceTest1 {
public static void main(String args[]) {
ObjIntConsumer<String> objIntConsumberObj = (t, value) -> { // lambda expression
if(t.length() > value) {
System.out.println("String is bigger than the expected value");
} else if(t.length() == value) {
System.out.println("String is equal to expected value");
} else {
System.out.println("String is shorter than the expected value");
}
}; // end of lambda expression
objIntConsumberObj.accept("tutorialspoint.com", 15);
objIntConsumberObj.accept("tutorix.com", 15);
}
}输出
String is bigger than the expected value String is shorter than the expected value
示例 2
import java.util.*;
import java.util.function.*;
public class ObjIntConsumerInterfaceTest2 {
public static void main(String args[]) {
ObjIntConsumer<List <Integer>> objIntConsumberObj = (t, value) -> { // lamnda expression
if(t.contains(value)) {
System.out.println("Expected value is present in the string");
} else {
System.out.println("Expected value is not present in the string");
}
}; // end of lambda expression
List<Integer> listObj = new ArrayList<Integer>();
listObj.add(55);
listObj.add(100);
listObj.add(75);
objIntConsumberObj.accept(listObj, 80);
objIntConsumberObj.accept(listObj, 100);
}
}输出
Expected value is not present in the string Expected value is present in the string
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