如何在 MySQL 的列中选择前 20 个字符之后的全部字符?


让我们先创建一个表 −

mysql> create table DemoTable
(
   Title text
);
Query OK, 0 rows affected (0.86 sec)

使用 insert 命令在表中插入一些记录 −

mysql> insert into DemoTable values('C is a good programming language to start');
Query OK, 1 row affected (0.18 sec)
mysql> insert into DemoTable values('Java is good with data structure and algorithm');
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable values('Coding is very important');
Query OK, 1 row affected (0.20 sec)

使用 select 语句显示表中的所有记录 −

mysql> select *from DemoTable;

这将生成以下输出 −

+------------------------------------------------+
| Title                                          |
+------------------------------------------------+
| C is a good programming language to start      |
| Java is good with data structure and algorithm |
| Coding is very important                       |
+------------------------------------------------+
3 rows in set (0.00 sec)

以下是选择前 20 个字符之后的所有字符的查询 −

mysql> select substring(Title from 20) from DemoTable;

这将生成以下输出 −

+-----------------------------+
| substring(Title from 20)    |
+-----------------------------+
| ming language to start      |
| ata structure and algorithm |
| rtant                       |
+-----------------------------+
3 rows in set (0.00 sec)

更新于: 2019 年 9 月 26 日

191 次浏览

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