如何在 MySQL 的列中选择前 20 个字符之后的全部字符?
让我们先创建一个表 −
mysql> create table DemoTable ( Title text ); Query OK, 0 rows affected (0.86 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable values('C is a good programming language to start'); Query OK, 1 row affected (0.18 sec) mysql> insert into DemoTable values('Java is good with data structure and algorithm'); Query OK, 1 row affected (0.19 sec) mysql> insert into DemoTable values('Coding is very important'); Query OK, 1 row affected (0.20 sec)
使用 select 语句显示表中的所有记录 −
mysql> select *from DemoTable;
这将生成以下输出 −
+------------------------------------------------+ | Title | +------------------------------------------------+ | C is a good programming language to start | | Java is good with data structure and algorithm | | Coding is very important | +------------------------------------------------+ 3 rows in set (0.00 sec)
以下是选择前 20 个字符之后的所有字符的查询 −
mysql> select substring(Title from 20) from DemoTable;
这将生成以下输出 −
+-----------------------------+ | substring(Title from 20) | +-----------------------------+ | ming language to start | | ata structure and algorithm | | rtant | +-----------------------------+ 3 rows in set (0.00 sec)
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