如何使用 CASE 语句更新获取的特定列值?
为此,请将 UPDATE 命令与 CASE 语句结合使用。我们首先创建一个表 -
mysql> create table DemoTable1925 ( StudentId int NOT NULL AUTO_INCREMENT PRIMARY KEY, StudentName varchar(20), StudentMarks int ); Query OK, 0 rows affected (0.00 sec)
使用 insert 命令在表中插入一些记录 -
mysql> insert into DemoTable1925(StudentName,StudentMarks) values('Chris',98); Query OK, 1 row affected (0.00 sec) mysql> insert into DemoTable1925(StudentName,StudentMarks) values('David',45); Query OK, 1 row affected (0.00 sec)
使用 select 语句显示表中的所有记录 -
mysql> select * from DemoTable1925;
这将生成以下输出 -
+-----------+-------------+--------------+ | StudentId | StudentName | StudentMarks | +-----------+-------------+--------------+ | 1 | Chris | 98 | | 2 | David | 45 | +-----------+-------------+--------------+ 2 rows in set (0.00 sec)
以下是使用 CASE 语句更新特定列值的查询 -
mysql> update DemoTable1925 set StudentMarks=case StudentMarks when 45 then 98 when 98 then 0 end where StudentMarks IN(45,98); Query OK, 2 rows affected (0.00 sec) Rows matched: 2 Changed: 2 Warnings: 0
让我们再次查看表记录 -
mysql> select * from DemoTable1925;
这将生成以下输出 -
+-----------+-------------+--------------+ | StudentId | StudentName | StudentMarks | +-----------+-------------+--------------+ | 1 | Chris | 0 | | 2 | David | 98 | +-----------+-------------+--------------+ 2 rows in set (0.00 sec)
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