数字与其各位数字之和的差大于s的数字

#include <iostream>
using namespace std;
// function to find the count of numbers with difference of more than s
int count(int n, int s){    
   // base condition 
   if(s == 0){
      // 1 to 9 have a difference of 0
      return n-9;
   }
   else{        
      // traversing over the number with the gap of 10
      int diff = 0; // variable to store the previous difference 
      for(int i = 10; i<n; i += 10){
         int cur = i;
         int digitSum = 0;
         while(cur){
            digitSum += cur%10;
            cur /= 10;
         }            
         diff = i-digitSum; 
         if(diff > s){
            return n-i+1;
         }
      }
      return 0;
   }
}
int main(){
   int n = 20;
   int s = 6;    
   cout<<"The total numbers with the difference between the number and sum of digits are greater than "<< s << " in the range of 1 to "<< n << " are: ";
   // calling to function 
   cout<<count(n,s)<<endl;
   return 0;
}

#include <bits/stdc++.h>
using namespace std;
// function to get the digit sum 
int digitSum(int cur){
   int sum = 0;
   while(cur){
      sum += cur%10;
      cur /= 10;
   }
   return sum;
}
// function to find the count of number with difference more than s
int count(int n, int s){    
   // getting number minimum of n and s + 163
   int mi =  min(n, s + 163);
   for(int i = s; i<= mi; i++){
      int sum = digitSum(i);
      if(i - sum > s){
         return n - i +1;
      }
   }
   return 0;    
}
int main(){
   int n = 1000;
   int s = 100;    
   cout<<"The total numbers with the difference between the number and sum of digits are greater than "<< s << " in the range of 1 to "<< n << " are: ";
   // calling to function 
   cout<<count(n,s)<<endl;
   return 0;
}