Prove that if a number is trebled then its cube is 27 times the cube of the given number.
To do:
We have to prove that if a number is tripled then its cube is 27 times the cube of the given number.
Solution:
Let the number be $a$.
Now,
Cube of $a = a \times a \times a$
$= a^3$
Tripling the number $a$, we get,
$3\times a=3a$
Cube of $3a = 3a \times 3a \times 3a$
$= 27a^3$
So,
We can see that if a number is tripled, then its cube is 27 times the cube of the
given number.
Hence proved.
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