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法律学用星号替换 C++ 中的单词
本程序的目标是使用 c++ 编程代码用星号替换字符串中的某个特定单词。向量和字符串类的基本函数在实现预期结果方面起着关键作用。算法如下：
算法
START Step-1: Input string Step-2 Split the string into words and store in array list Step-3: Iterate the loop till the length and put the asterisk into a variable Step-4: Traverse the array foreah loop and compare the string with the replaced word Step-5: Print END
现在，根据算法编写以下代码。在此，string 的 strtok() 方法分割字符串并返回向量类数组列表类型。
示例
#include <cstring>
#include <iostream>
#include <vector>
#include <string.h>
//method for spliting string
std::vector<std::string> split(std::string str,std::string sep){
char* cstr=const_cast<char*>(str.c_str());
char* current;
std::vector<std::string> arr;
current=strtok(cstr,sep.c_str());
while(current!=NULL){
arr.push_back(current);
current=strtok(NULL,sep.c_str());
}
return arr;
}
int main(){
std::vector<std::string> word_list;
std::cout<<"string before replace::"<<"Hello ajay yadav ! you ajay you are star"<<std::endl;
std::cout<<"word to be replaced::"<<"ajay"<<std::endl;
word_list=split("Hello ajay yadav ! you ajay you are star"," ");
std::string result = "";
// Creating the censor which is an asterisks
// "*" text of the length of censor word
std::string stars = "";
std::string word = "ajay";
for (int i = 0; i < word.length(); i++)
stars += '*';
// Iterating through our list
// of extracted words
int index = 0;
for (std::string i : word_list){
if (i.compare(word) == 0)
// changing the censored word to
// created asterisks censor
word_list[index] = stars;
index++;
}
// join the words
for (std::string i : word_list){
result += i + ' ';
}
std::cout<<"output::"<<result;
return 0;
}
}如上代码所示，所有字符串操作代码都捆绑在 retrieveChar() 方法中，稍后会将其调用传递给程序 main() 执行。
输出
String before replace::Hello ajay yadav ! you ajay you are star Word to be replaced::ajay Output::Hello **** yadav ! you **** you are star
更新时间：29-Nov-2019
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