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时尚研究
法律研究Java 中 ShortBuffer compareTo() 方法
可以使用 java.nio.ShortBuffer 类中的 compareTo() 方法将一个缓冲区与另一个缓冲区进行比较。如果缓冲区小于给定的缓冲区，则此方法返回一个负整数；如果缓冲区等于给定的缓冲区，则返回零；如果缓冲区大于给定的缓冲区，则返回一个正整数。
演示此方法的程序如下 −
示例
import java.nio.*;
import java.util.*;
public class Demo {
public static void main(String[] args) {
int n = 5;
try {
ShortBuffer buffer1 = ShortBuffer.allocate(n);
buffer1.put((short)12);
buffer1.put((short)91);
buffer1.put((short)25);
buffer1.put((short)18);
buffer1.put((short)30);
buffer1.rewind();
System.out.println("The first ShortBuffer is: " + Arrays.toString(buffer1.array()));
ShortBuffer buffer2 = ShortBuffer.allocate(n);
buffer2.put((short)12);
buffer2.put((short)91);
buffer2.put((short)25);
buffer2.put((short)18);
buffer2.put((short)30);
buffer2.rewind();
System.out.println("The second ShortBuffer is: " + Arrays.toString(buffer2.array()));
int val = buffer1.compareTo(buffer2);
if (val == 0)
System.out.println("
Both the buffers are lexicographically equal");
else if (val > 0)
System.out.println("
The first buffer is lexicographically greater than the second buffer");
else
System.out.println("
The second buffer is lexicographically greater than the first buffer");
} catch (IllegalArgumentException e) {
System.out.println("Error!!! IllegalArgumentException");
} catch (ReadOnlyBufferException e) {
System.out.println("Error!!! ReadOnlyBufferException");
}
}
}输出
The first ShortBuffer is: [12, 91, 25, 18, 30] The second ShortBuffer is: [12, 91, 25, 18, 30] Both the buffers are lexicographically equal
更新时间： 2019 年 7 月 30 日
68 次浏览
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