C 程序比较两个矩阵是否相等
用户必须输入两个矩阵的阶数和元素。然后,对这两个矩阵进行比较。
如果两个矩阵元素及阶数相等,则显示这两个矩阵相等。
如果矩阵阶数相等,但元素不相等,则显示可以对矩阵进行比较,但不相等。
如果阶数和元素都不匹配,则显示无法比较这些矩阵。
程序
以下是 C 程序,用于比较两个矩阵是否相等 -
#include <stdio.h> #include <conio.h> main(){ int A[10][10], B[10][10]; int i, j, R1, C1, R2, C2, flag =1; printf("Enter the order of the matrix A
"); scanf("%d %d", &R1, &C1); printf("Enter the order of the matrix B
"); scanf("%d %d", &R2,&C2); printf("Enter the elements of matrix A
"); for(i=0; i<R1; i++){ for(j=0; j<C1; j++){ scanf("%d",&A[i][j]); } } printf("Enter the elements of matrix B
"); for(i=0; i<R2; i++){ for(j=0; j<C2; j++){ scanf("%d",&B[i][j]); } } printf("MATRIX A is
"); for(i=0; i<R1; i++){ for(j=0; j<C1; j++){ printf("%3d",A[i][j]); } printf("
"); } printf("MATRIX B is
"); for(i=0; i<R2; i++){ for(j=0; j<C2; j++){ printf("%3d",B[i][j]); } printf("
"); } /* Comparing two matrices for equality */ if(R1 == R2 && C1 == C2){ printf("Matrices can be compared
"); for(i=0; i<R1; i++){ for(j=0; j<C2; j++){ if(A[i][j] != B[i][j]){ flag = 0; break; } } } } else{ printf(" Cannot be compared
"); exit(1); } if(flag == 1 ) printf("Two matrices are equal
"); else printf("But,two matrices are not equal
"); }
输出
当执行以上程序时,会生成以下结果 -
Run 1: Enter the order of the matrix A 2 2 Enter the order of the matrix B 2 2 Enter the elements of matrix A 1 2 3 4 Enter the elements of matrix B 1 2 3 4 MATRIX A is 1 2 3 4 MATRIX B is 1 2 3 4 Matrices can be compared Two matrices are equal Run 2: Enter the order of the matrix A 2 2 Enter the order of the matrix B 2 2 Enter the elements of matrix A 1 2 3 4 Enter the elements of matrix B 5 6 7 8 MATRIX A is 1 2 3 4 MATRIX B is 5 6 7 8 Matrices can be compared But,two matrices are not equal
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