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法律研究生成给定数字列表的所有可能组合的 C++ 程序
这是一个用于生成一个给定数字列表的所有可能组合的 C++ 程序
算法
Begin Take the number of elements and the elements as input. function Combi(char a[], int reqLen, int s, int currLen, bool check[], int l) : If currLen>reqLen then Return Else if currLen=reqLen then Then print the new generated sequence. If s=l then Then return no further element is left. For every index there are two option: either proceed with a start as ‘true’ and recursively call Combi() with incremented value of ‘currLen’ and ‘s’. Or proceed with a start as ‘false’ and recursively call Combi() with only incremented value of ‘s’. End
示例
#include<iostream>
using namespace std;
void Combi(char a[], int reqLen, int s, int currLen, bool check[], int l)
// print the all possible combination of given array set
{
if(currLen > reqLen)
return;
else if (currLen == reqLen) {
cout<<"\t";
for (int i = 0; i < l; i++) {
if (check[i] == true) {
cout<<a[i]<<" ";
}
}
cout<<"\n";
return;
}
if (s == l) {
return;
}
check[s] = true;
Combi(a, reqLen, s + 1, currLen + 1, check, l);
//recursively call Combi() with incremented value of ‘currLen’ and ‘s’.
check[s] = false;
Combi(a, reqLen, s + 1, currLen, check, l);
// recursively call Combi() with only incremented value of ‘s’.
}
int main() {
int i,n;
bool check[n];
cout<<"Enter the number of element array have: ";
cin>>n;
char a[n];
cout<<"\n";
for(i = 0; i < n; i++) {
cout<<"Enter "<<i+1<<" element: ";
cin>>a[i];
check[i] = false;
}
for(i = 1; i <= n; i++) {
cout<<"\nThe all possible combination of length "<<i<<" for the given array set:\n";
Combi(a, i, 0, 0, check, n);
}
return 0;
}输出
Enter the number of element array have: 4 Enter 1 element: 4 Enter 2 element: 3 Enter 3 element: 2 Enter 4 element: 1 The all possible combination of length 1 for the given array set: 4 3 2 1 The all possible combination of length 2 for the given array set: 4 3 4 2 4 1 3 2 3 1 2 1 The all possible combination of length 3 for the given array set: 4 3 2 4 3 1 4 2 1 3 2 1 The all possible combination of length 4 for the given array set: 4 3 2 1
更新于：30-Jul-2019
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