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Legal StudiesC++ 程序：生成 N 个长度为 M 的密码
这是一个 C++ 程序，用于生成 N 个长度为 M 的密码。
算法
Begin Take the length of password as input. function permutation() generate random passwords: /* Arguments A pointer array a. Total Number of random numbers m. Length of the password s. */ // Body of the function: if (m == s) for i = 0 to s-1 Print *(a + i) else for i = m to s-1 int tmp = a[m] a[m] = a[i] a[i] = tmp Call permutation(a, m + 1, s) tmp = a[m] a[m] = a[i] a[i] = tmp End
示例
#include<iostream>
#include<conio.h>
#include<stdlib.h>
using namespace std;
void permutation(int *a, int m, int s) {
if (m == s) {
for (int i = 0; i < s; i++) {
cout << *(a + i);
}
cout << endl;
} else {
for (int i = m; i < s; i++) {
int tmp = a[m];
a[m] = a[i];
a[i] = tmp;
permutation(a, m + 1, s);
tmp = a[m];
a[m] = a[i];
a[i] = tmp;
}
}
}
int main(int argc, char **argv) {
cout << "Enter the length of the password: ";
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) {
a[i] = rand() % 10; //randomly generate numbers
}
cout <<"Random Numbers are:" <<endl;
for (int i = 0; i < n; i++) {
cout<<a[i] <<endl;
}
cout << "The Passwords are: "<<endl;
permutation(a, 0, n);
}输出
Enter the length of the password: 4 Random Numbers are: 1740T he Passwords are: 1740 1704 1470 1407 1047 1074 7140 7104 7410 7401 7041 7014 4710 4701 4170 4107 4017 4071 0741 0714 0471 0417 0147 0174
更新于：30-Jul-2019
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