C# 中的 Decimal.ToInt32() 方法


C# 中的 Decimal.ToInt32() 方法用于将指定十进制的值转换为等效的 32 位带符号整数。

语法

以下是对应的语法 −

public static int ToInt32 (decimal val);

上文,Val 为要转换的十进制数。

示例

现在让我们看一个示例,实现 Decimal.ToInt32() 方法 −

using System;
public class Demo {
   public static void Main(){
      Decimal val1 = 0.001m;
      Decimal val2 = 1.000m;
      Console.WriteLine("Decimal 1 = "+val1);
      Console.WriteLine("Decimal 2 = "+val2);
      int res1 = Decimal.ToInt32(val1);
      int res2 = Decimal.ToInt32(val2);
      Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res1);
      Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res2);
   }
}

输出

这将产生以下输出 −

Decimal 1 = 0.001
Decimal 2 = 1.000
32-bit signed integer (value1) (Decimal to signed integer) = 0
32-bit signed integer (value1) (Decimal to signed integer) = 1

示例

现在让我们看另一个示例,实现 Decimal.ToInt32() 方法 −

using System;
public class Demo {
   public static void Main(){
      Decimal val1 = -3.578m;
      Decimal val2 = 9.352m;
      Console.WriteLine("Decimal 1 = "+val1);
      Console.WriteLine("Decimal 2 = "+val2);
      int res1 = Decimal.ToInt32(val1);
      int res2 = Decimal.ToInt32(val2);
      Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res1);
      Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res2);
   }
}

输出

这将产生以下输出 −

Decimal 1 = -3.578
Decimal 2 = 9.352
32-bit signed integer (value1) (Decimal to signed integer) = -3
32-bit signed integer (value1) (Decimal to signed integer) = 9

更新于: 12-11-2019

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