C# 中的 Decimal.ToInt32() 方法
C# 中的 Decimal.ToInt32() 方法用于将指定十进制的值转换为等效的 32 位带符号整数。
语法
以下是对应的语法 −
public static int ToInt32 (decimal val);
上文,Val 为要转换的十进制数。
示例
现在让我们看一个示例,实现 Decimal.ToInt32() 方法 −
using System;
public class Demo {
public static void Main(){
Decimal val1 = 0.001m;
Decimal val2 = 1.000m;
Console.WriteLine("Decimal 1 = "+val1);
Console.WriteLine("Decimal 2 = "+val2);
int res1 = Decimal.ToInt32(val1);
int res2 = Decimal.ToInt32(val2);
Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res1);
Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res2);
}
}输出
这将产生以下输出 −
Decimal 1 = 0.001 Decimal 2 = 1.000 32-bit signed integer (value1) (Decimal to signed integer) = 0 32-bit signed integer (value1) (Decimal to signed integer) = 1
示例
现在让我们看另一个示例,实现 Decimal.ToInt32() 方法 −
using System;
public class Demo {
public static void Main(){
Decimal val1 = -3.578m;
Decimal val2 = 9.352m;
Console.WriteLine("Decimal 1 = "+val1);
Console.WriteLine("Decimal 2 = "+val2);
int res1 = Decimal.ToInt32(val1);
int res2 = Decimal.ToInt32(val2);
Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res1);
Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res2);
}
}输出
这将产生以下输出 −
Decimal 1 = -3.578 Decimal 2 = 9.352 32-bit signed integer (value1) (Decimal to signed integer) = -3 32-bit signed integer (value1) (Decimal to signed integer) = 9
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