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法律研究获取 C# 中 ListDictionary 中包含的关键值对数
要获得 ListDictionary 中包含的关键值对数，代码如下−
示例
using System;
using System.Collections;
using System.Collections.Specialized;
public class Demo {
public static void Main(){
ListDictionary dict1 = new ListDictionary();
dict1.Add("A", "Books");
dict1.Add("B", "Electronics");
dict1.Add("C", "Smart Wearables");
dict1.Add("D", "Pet Supplies");
dict1.Add("E", "Clothing");
dict1.Add("F", "Footwear");
Console.WriteLine("ListDictionary1 elements...");
foreach(DictionaryEntry d in dict1){
Console.WriteLine(d.Key + " " + d.Value);
}
ListDictionary dict2 = new ListDictionary();
dict2.Add("1", "One");
dict2.Add("2", "Two");
dict2.Add("3", "Three");
dict2.Add("4", "Four");
dict2.Add("5", "Five");
dict2.Add("6", "Six");
Console.WriteLine("
ListDictionary2 elements...");
foreach(DictionaryEntry d in dict2){
Console.WriteLine(d.Key + " " + d.Value);
}
Console.WriteLine("Count of key/value pairs in Dictionary 2 = "+dict2.Count);
ListDictionary dict3 = new ListDictionary();
dict3 = dict2;
Console.WriteLine("
Is ListDictionary3 equal to ListDictionary2? = "+(dict3.Equals(dict2)));
dict3.Clear();
Console.WriteLine("Count of key/value pairs in Dictionary 3 = "+dict3.Count);
}
}输出
这会产生以下输出 −
ListDictionary1 elements... A Books B Electronics C Smart Wearables D Pet Supplies E Clothing F Footwear ListDictionary2 elements... 1 One 2 Two 3 Three 4 Four 5 Five 6 Six Count of key/value pairs in Dictionary 2 = 6 Is ListDictionary3 equal to ListDictionary2? = True Count of key/value pairs in Dictionary 3 = 0
示例
我们来看另一个示例−
using System;
using System.Collections;
using System.Collections.Specialized;
public class Demo {
public static void Main(){
ListDictionary dict1 = new ListDictionary();
dict1.Add("A", "Books");
dict1.Add("B", "Electronics");
dict1.Add("C", "Smart Wearables");
dict1.Add("D", "Pet Supplies");
dict1.Add("E", "Clothing");
Console.WriteLine("ListDictionary1 elements...");
foreach(DictionaryEntry d in dict1){
Console.WriteLine(d.Key + " " + d.Value);
}
Console.WriteLine("Count of key/value pairs in Dictionary1 = "+dict1.Count);
ListDictionary dict2 = new ListDictionary();
dict2.Add("1", "One");
dict2.Add("2", "Two");
dict2.Add("3", "Three");
dict2.Add("4", "Four");
dict2.Add("5", "Five");
dict2.Add("6", "Six");
Console.WriteLine("
ListDictionary2 key-value pairs...");
IDictionaryEnumerator demoEnum = dict2.GetEnumerator();
while (demoEnum.MoveNext())
Console.WriteLine("Key = " + demoEnum.Key + ", Value = "+ demoEnum.Value);
Console.WriteLine("Count of key/value pairs in Dictionary2 = "+dict2.Count);
}
}输出
这会产生以下输出 −
ListDictionary1 elements... A Books B Electronics C Smart Wearables D Pet Supplies E Clothing Count of key/value pairs in Dictionary1 = 5 ListDictionary2 key-value pairs... Key = 1, Value = One Key = 2, Value = Two Key = 3, Value = Three Key = 4, Value = Four Key = 5, Value = Five Key = 6, Value = Six Count of key/value pairs in Dictionary2 = 6
更新时间：06-12-2019
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