计数 C# 中 HybridDictionary 键/值对的数量
以下为 HybridDictionary 中键/值对的数量的代码 -
示例
using System; using System.Collections; using System.Collections.Specialized; public class Demo { public static void Main(){ HybridDictionary dict1 = new HybridDictionary(); dict1.Add("A", "SUV"); dict1.Add("B", "MUV"); dict1.Add("C", "AUV"); Console.WriteLine("HybridDictionary1 elements..."); foreach(DictionaryEntry d in dict1){ Console.WriteLine(d.Key + " " + d.Value); } Console.WriteLine("Count of Key/value pairs in Dictionary1 = "+dict1.Count); HybridDictionary dict2 = new HybridDictionary(); dict2.Add("1", "One"); dict2.Add("2", "Two"); dict2.Add("3", "Three"); dict2.Add("4", "Four"); dict2.Add("5", "Five"); dict2.Add("6", "Six"); Console.WriteLine("
HybridDictionary2 elements..."); foreach(DictionaryEntry d in dict2){ Console.WriteLine(d.Key + " " + d.Value); } Console.WriteLine("Count of Key/value pairs in Dictionary2 = "+dict1.Count); dict2.Clear(); Console.WriteLine("Count of Key/value pairs in Dictionary2 (Updated) = "+dict2.Count); } }
输出
这将产生以下输出 -
HybridDictionary1 elements... A SUV B MUV C AUV Count of Key/value pairs in Dictionary1 = 3 HybridDictionary2 elements... 1 One 2 Two 3 Three 4 Four 5 Five 6 Six Count of Key/value pairs in Dictionary2 = 3 Count of Key/value pairs in Dictionary2 (Updated) = 0
示例
现在让我们看另一个示例 -
using System; using System.Collections; using System.Collections.Specialized; public class Demo { public static void Main(){ HybridDictionary dict = new HybridDictionary(); dict.Add("A", "SUV"); dict.Add("B", "MUV"); dict.Add("C", "AUV"); Console.WriteLine("HybridDictionary elements..."); foreach(DictionaryEntry d in dict){ Console.WriteLine(d.Key + " " + d.Value); } Console.WriteLine("Count of Key/value pairs in Dictionary = "+dict.Count); dict.Add("D", "Utility Vehicle"); dict.Add("E", "Convertible"); Console.WriteLine("Count of Key/value pairs in Dictionary (Updated) = "+dict.Count); } }
输出
这将产生以下输出 -
HybridDictionary elements... A SUV B MUV C AUV Count of Key/value pairs in Dictionary = 3 Count of Key/value pairs in Dictionary (Updated) = 5
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