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法律研究在 C# 中检查 HybridDictionary 的特定键
为了检查指定键的 HybridDictionary，代码如下 -
示例
using System;
using System.Collections;
using System.Collections.Specialized;
public class Demo {
public static void Main(){
HybridDictionary dict = new HybridDictionary(5);
dict.Add("A", "AB");
dict.Add("B", "BC");
dict.Add("C", "DE");
dict.Add("D", "FG");
dict.Add("E", "HI");
Console.WriteLine("Key/Value pairs...");
foreach(DictionaryEntry d in dict)
Console.WriteLine("Key = "+d.Key + ", Value = " + d.Value);
Console.WriteLine("Does HybridDictionary contains the key C? = "+dict.Contains("C"));
}
}结果
这将产生以下结果 -
Key/Value pairs... Key = A, Value = AB Key = B, Value = BC Key = C, Value = DE Key = D, Value = FG Key = E, Value = HI Does HybridDictionary contains the key C? = True
示例
现在让我们看另一个示例 -
using System;
using System.Collections;
using System.Collections.Specialized;
public class Demo {
public static void Main(){
HybridDictionary dict1 = new HybridDictionary();
dict1.Add("A", "Books");
dict1.Add("B", "Electronics");
dict1.Add("C", "Smart Wearables");
dict1.Add("D", "Pet Supplies");
dict1.Add("E", "Clothing");
dict1.Add("F", "Footwear");
Console.WriteLine("HybridDictionary1 elements...");
foreach(DictionaryEntry d in dict1){
Console.WriteLine(d.Key + " " + d.Value);
}
Console.WriteLine("Count of Key/value pairs in Dictionary1 = "+dict1.Count);
HybridDictionary dict2 = new HybridDictionary();
dict2.Add("1", "One");
dict2.Add("2", "Two");
dict2.Add("3", "Three");
dict2.Add("4", "Four");
dict2.Add("5", "Five");
dict2.Add("6", "Six");
Console.WriteLine("
HybridDictionary2 elements...");
foreach(DictionaryEntry d in dict2){
Console.WriteLine(d.Key + " " + d.Value);
}
Console.WriteLine("Count of Key/value pairs in Dictionary2 = "+dict1.Count);
Console.WriteLine("Does HybridDictionary2 contains the key 10? = "+dict2.Contains(10));
dict2.Clear();
Console.WriteLine("Count of Key/value pairs in Dictionary2 (Updated) = "+dict2.Count);
}
}结果
这将产生以下结果 -
HybridDictionary1 elements... A Books B Electronics C Smart Wearables D Pet Supplies E Clothing F Footwear Count of Key/value pairs in Dictionary1 = 6 HybridDictionary2 elements... 1 One 2 Two 3 Three 4 Four 5 Five 6 Six Count of Key/value pairs in Dictionary2 = 6 Does HybridDictionary2 contains the key 10? = False Count of Key/value pairs in Dictionary2 (Updated) = 0
更新时间：11-12-2019
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