如何统计MongoDB 中游标的迭代次数?
您需要使用 while 循环以及 find() 游标的帮助来使用自定义逻辑。让我们创建一个带有文档的集合 -
> db.demo724.insertOne( ... { ... details: ... { ... id:101, ... otherDetails:[ ... {Name:"Chris"} ... ] ... } ... } ... ); { "acknowledged" : true, "insertedId" : ObjectId("5eab0cce43417811278f5890") } > > > db.demo724.insertOne( ... { ... ... } ... ); { "acknowledged" : true, "insertedId" : ObjectId("5eab0cce43417811278f5891") } > db.demo724.insertOne( ... { ... details: ... { ... id:1001 ... } ... } ... ); { "acknowledged" : true, "insertedId" : ObjectId("5eab0cce43417811278f5892") }
利用 find() 方法从集合中显示所有文档 -
> db.demo724.find();
这将生成以下输出 &miinus;
{ "_id" : ObjectId("5eab0cce43417811278f5890"), "details" : { "id" : 101, "otherDetails" : [ { "Name" : "Chris" } ] } } { "_id" : ObjectId("5eab0cce43417811278f5891") } { "_id" : ObjectId("5eab0cce43417811278f5892"), "details" : { "id" : 1001 } }
这是在 MongoDB 中统计游标迭代的查询 -
> var c=db.demo724.find(); > var detailsCount=0; > while (c.hasNext()) { ... var current = c.next(); ... if (typeof current["details"] != "undefined") { ... detailsCount++; ... } ... } 1 > print("number of details: " + detailsCount);
这会产生以下输出 -
number of details: 2
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