如何使用 Java 将 JSON 解析为 Gson 树模型?
Gson 库可用于将 JSON 字符串解析为树模型。我们可以使用 JsonParser 将JSON 字符串解析为 JSON 元素类型的树模型。JsonElement 的 getAsJsonObject() 方法可用于将元素获取为 JsonObject,JsonElement 的 getAsJsonArray() 方法可用于将元素获取为 JsonArray。
语法
public JsonObject getAsJsonObject() public JsonArray getAsJsonArray()
示例
import java.util.List; import com.google.gson.*; public class JsonTreeModelTest { public static void main(String args[]){ String jsonStr = "{\"name\":\"Adithya\",\"age\":20,\"year of passout\":2005,\"subjects\": [\"MATHEMATICS\",\"PHYSICS\",\"CHEMISTRY\"]}"; JsonParser jsonParser = new JsonParser(); JsonElement jsonElement = jsonParser.parse(jsonStr); if(jsonElement.isJsonObject()) { JsonObject studentObj = jsonElement.getAsJsonObject(); System.out.println("Student Info:"); System.out.println("Name is: " + studentObj.get("name")); System.out.println("Age is: " + studentObj.get("age")); System.out.println("Year of Passout: " + studentObj.get("year of passout")); JsonArray jsonArray = studentObj.getAsJsonArray("subjects"); System.out.println("Subjects:" + jsonArray); } } } // Student class class Student { private String name; private int age; private int passoutYear; private List subjects; public Student(String name, int age, int passoutYear, List subjects) { this.name = name; this.age = age; this.passoutYear = passoutYear; this.subjects = subjects; } @Override public String toString() { return "Student{" + "name='" + name + '\'' + ", age='" + age + '\'' + ", year of passout=" + passoutYear + ", subjects=" + subjects + '}'; } }
输出
Student Info: Name is: "Adithya" Age is: 20 Year of Passout: 2005 Subjects:["MATHEMATICS","PHYSICS","CHEMISTRY"]
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