如何使用 MongoDB 选取每个组中的最大值?


可以使用 $group。让我们创建一个包含文档的集合 −

> db.demo659.insertOne({Name:"Chris",CountryName:"US","Marks":50});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5ea1a50724113ea5458c7cf9")
}
> db.demo659.insertOne({Name:"David",CountryName:"US","Marks":60});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5ea1a50724113ea5458c7cfa")
}
> db.demo659.insertOne({Name:"Mike",CountryName:"US","Marks":55});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5ea1a50724113ea5458c7cfb")
}
> db.demo659.insertOne({Name:"Chris",CountryName:"UK","Marks":75});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5ea1a50724113ea5458c7cfc")
}
> db.demo659.insertOne({Name:"David",CountryName:"UK","Marks":54});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5ea1a50724113ea5458c7cfd")
}
> db.demo659.insertOne({Name:"Mike",CountryName:"UK","Marks":72});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5ea1a50824113ea5458c7cfe")
}

借助 find() 方法来显示集合中的所有文档 −

> db.demo659.find();

这将生成以下输出。它查找每个文档(即 CountryName US 和 UK)中的最高分 −

{ "_id" : ObjectId("5ea1a50724113ea5458c7cf9"), "Name" : "Chris", "CountryName" : "US", "Marks" : 50 }
{ "_id" : ObjectId("5ea1a50724113ea5458c7cfa"), "Name" : "David", "CountryName" : "US", "Marks" : 60 }
{ "_id" : ObjectId("5ea1a50724113ea5458c7cfb"), "Name" : "Mike", "CountryName" : "US", "Marks" : 55 }
{ "_id" : ObjectId("5ea1a50724113ea5458c7cfc"), "Name" : "Chris", "CountryName" : "UK", "Marks" : 75 }
{ "_id" : ObjectId("5ea1a50724113ea5458c7cfd"), "Name" : "David", "CountryName" : "UK", "Marks" : 54 }
{ "_id" : ObjectId("5ea1a50824113ea5458c7cfe"), "Name" : "Mike", "CountryName" : "UK", "Marks" : 72 }

以下是查询以选择每个组中的最大值 −

> db.demo659.aggregate( { $group: {
...    _id: {CountryName: "$CountryName" },
...    'MaxMarks': { $max : "$Marks" }
... }})

这将生成以下输出 −

{ "_id" : { "CountryName" : "UK" }, "MaxMarks" : 75 }
{ "_id" : { "CountryName" : "US" }, "MaxMarks" : 60 }

更新于: 13-May-2020

350 次浏览

开启您的 职业生涯

完成课程获得认证

开始学习
广告