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Legal Studies如何使用 MySQL 更新 datetime 字段的日期？
使用算术运算符减号 (-) 更新 datetime 字段的日期。
语法如下
update yourTableName set yourDateTimeColumnName=yourDateTimeColumnName - interval yourValue day where date(yourDateTimeColumnName)=’yourDateValue’;
为了理解上述语法，我们来创建一个表。创建表的查询如下
mysql> create table updateDateDemo -> ( -> Id int NOT NULL AUTO_INCREMENT PRIMARY KEY, -> ArrivalDate datetime -> ); Query OK, 0 rows affected (0.66 sec)
使用插入命令在表中插入一些记录。
查询如下
mysql> insert into updateDateDemo(ArrivalDate) values('2011-01-13');
Query OK, 1 row affected (0.19 sec)
mysql> insert into updateDateDemo(ArrivalDate) values('2013-04-21');
Query OK, 1 row affected (0.11 sec)
mysql> insert into updateDateDemo(ArrivalDate) values('2016-12-22');
Query OK, 1 row affected (0.14 sec)
mysql> insert into updateDateDemo(ArrivalDate) values('2017-02-25');
Query OK, 1 row affected (0.27 sec)
mysql> insert into updateDateDemo(ArrivalDate) values('2018-08-19');
Query OK, 1 row affected (0.17 sec)
mysql> insert into updateDateDemo(ArrivalDate) values('2019-02-27');
Query OK, 1 row affected (0.24 sec)使用 select 语句显示表中的所有记录。
查询如下
mysql> select *from updateDateDemo;
以下为输出
+----+---------------------+ | Id | ArrivalDate | +----+---------------------+ | 1 | 2011-01-13 00:00:00 | | 2 | 2013-04-21 00:00:00 | | 3 | 2016-12-22 00:00:00 | | 4 | 2017-02-25 00:00:00 | | 5 | 2018-08-19 00:00:00 | | 6 | 2019-02-27 00:00:00 | +----+---------------------+ 6 rows in set (0.00 sec)
这里是对 datetime 字段的日期进行更新的查询
mysql> update updateDateDemo -> set ArrivalDate=ArrivalDate-interval 7 day -> where date(ArrivalDate)='2019-02-27'; Query OK, 1 row affected (0.13 sec) Rows matched: 1 Changed: 1 Warnings: 0
现在从表中检查更新的记录
mysql> select *from updateDateDemo;
以下为输出
+----+---------------------+ | Id | ArrivalDate | +----+---------------------+ | 1 | 2011-01-13 00:00:00 | | 2 | 2013-04-21 00:00:00 | | 3 | 2016-12-22 00:00:00 | | 4 | 2017-02-25 00:00:00 | | 5 | 2018-08-19 00:00:00 | | 6 | 2019-02-20 00:00:00 | +----+---------------------+ 6 rows in set (0.00 sec)
更新日期：30-Jul-2019
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