Java 程序,将数学字符串转换为 int
要评估数学字符串为 int,请在 Java 中使用 Nashorn JavaScript,即脚本。Nashorn 唤起动态特性,它是在 Java 7 中引入的,可用于提升性能。
对于脚本,请使用 ScriptEngineManager 类作为引擎
ScriptEngineManager scriptEngineManager = new ScriptEngineManager();
ScriptEngine scriptEngine = scriptEngineManager.getEngineByName("nashorn");现在,请使用 put() 在脚本引擎的状态中设置键值对
scriptEngine.put("one", 10);
scriptEngine.put("two", 50);
scriptEngine.put("three", 40);现在,这里有数学字符串。请使用 eval 进行评估
String strExp = "(one + two - three) == 20"; Object evalExp = scriptEngine.eval(strExp);
示例
import javax.script.ScriptEngine;
import javax.script.ScriptEngineManager;
import javax.script.ScriptException;
public class Demo {
public static void main(String[] args) {
ScriptEngineManager scriptEngineManager = new ScriptEngineManager();
ScriptEngine scriptEngine = scriptEngineManager.getEngineByName("nashorn");
scriptEngine.put("one", 10);
scriptEngine.put("two", 50);
scriptEngine.put("three", 40);
try {
String strExp = "(one + two - three) == 20";
Object evalExp = scriptEngine.eval(strExp);
System.out.println("Is "+strExp + " ? " + evalExp);
} catch (ScriptException se) {
se.printStackTrace();
}
}
}输出
Is (one + two - three) == 20 ? true
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