JavaScript 匹配 2 个数组
假设我们有两个数组,一个字符串文字数组,另一个对象数组。
const data = [{
name: 'Kamlesh Kapasi',
uid: 123
}, {
name: 'Mahesh Babu',
uid: 129
}, {
name: 'Akshay Kapoor',
uid: 223
}, {
name: 'Vikas Gupta',
uid: 423
}, {
name: 'Mohit Dalal',
uid: 133
}, {
name: 'Rajkumar Hirani',
uid: 233
}, {
name: 'Joy',
uid: 127
}];
const names = ['Joy', 'Rajkumar Hirani', 'Akshay Kapoor', 'Mahesh Babu',
'Mohit Dalal', 'Kamlesh Kapasi', 'Vikas Gupta']我们的工作是编写一个函数,该函数会迭代 names 数组,然后构建一个数字数组,其中包含与 names 数组中名称顺序相同的特定名称的 uid。
让我们来编写此函数的代码 −
示例
const data = [{
name: 'Kamlesh Kapasi',
uid: 123
}, {
name: 'Mahesh Babu',
uid: 129
}, {
name: 'Akshay Kapoor',
uid: 223
}, {
name: 'Vikas Gupta',
uid: 423
}, {
name: 'Mohit Dalal',
uid: 133
}, {
name: 'Rajkumar Hirani',
uid: 233
}, {
name: 'Joy',
uid: 127
}];
const names = ['Joy', 'Rajkumar Hirani', 'Akshay Kapoor', 'Mahesh Babu',
'Mohit Dalal', 'Kamlesh Kapasi', 'Vikas Gupta']
const mapId = (arr, names) => {
return names.reduce((acc, val) => {
const index = arr.findIndex(el => el.name === val);
return acc.concat(arr[index].uid);
}, []);
}
console.log(mapId(data, names));输出
控制台中的输出将是 −
[ 127, 233, 223, 129, 133, 123, 423 ]
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