C# 中的 Math.Max() 方法


C# 中的 Math.Max() 方法用于返回两个指定数字中较大的数字。该方法适用于两个数字都是 Double、Decimal、Int16、Int32 等的情况。

语法

以下是语法 −

public static ulong Max (ulong val1, ulong val2);
public static uint Max (uint val1, uint val2);
public static ushort Max (ushort val1, ushort val2);
public static float Max (float val1, float val2);
public static byte Max (byte val1, byte val2);
public static long Max (long val1, long val2);

示例

现在让我们看一个实现 Math.Max() 方法的示例 −

using System;
public class Demo {
   public static void Main(){
      byte val1 = 10, val2 = 15;
      decimal val3 = 1000M, val4 = 1500M;
      double val5 = 15.896745, val6 = 25.676843;
      short val7 = 20, val8 = 30;
      Console.WriteLine("Maximum Value from two byte values = "+Math.Max(val1, val2));
      Console.WriteLine("Maximum Value from two decimal values = "+Math.Max(val3, val4));
      Console.WriteLine("Maximum Value from two double values = "+Math.Max(val5, val6));
      Console.WriteLine("Maximum Value from two short values = "+Math.Max(val7, val8));
   }
}

输出

将产生以下输出 −

Maximum Value from two byte values = 15
Maximum Value from two decimal values = 1500
Maximum Value from two double values = 25.676843
Maximum Value from two short values = 30

示例

让我们看另一个实现 Math.Max() 方法的示例 −

using System;
public class Demo {
   public static void Main(){
      int val1 = 10, val2 = 15;
      float val3 = 10.8f, val4 = 25.6f;
      Console.WriteLine("Maximum Value from two int values = "+Math.Max(val1, val2));
      Console.WriteLine("Maximum Value from two float values = "+Math.Max(val3, val4));
   }
}

输出

将产生以下输出 −

Maximum Value from two int values = 15
Maximum Value from two float values = 25.6

更新于: 06-11-2019

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