找出包含其他列值中最大计数值的记录的 MySQL 查询？

为此，请使用 GROUP BY HAVING 子句。让我们首先创建一个表 -

mysql> create table DemoTable
(
   Value int
);
Query OK, 0 rows affected (0.54 sec)

使用 insert 命令在表中插入一些记录 -

mysql> insert into DemoTable values(88);
Query OK, 1 row affected (0.22 sec)
mysql> insert into DemoTable values(88);
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable values(88);
Query OK, 1 row affected (0.09 sec)
mysql> insert into DemoTable values(99);
Query OK, 1 row affected (0.09 sec)
mysql> insert into DemoTable values(99);
Query OK, 1 row affected (0.09 sec)
mysql> insert into DemoTable values(99);
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable values(99);
Query OK, 1 row affected (0.07 sec)
mysql> insert into DemoTable values(100);
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable values(100);
Query OK, 1 row affected (0.07 sec)
mysql> insert into DemoTable values(88);
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable values(88);
Query OK, 1 row affected (0.11 sec)

使用 select 语句显示表中的所有记录 -

mysql> select *from DemoTable;

这将产生以下输出 -

+-------+
| Value |
+-------+
|    88 |
|    88 |
|    88 |
|    99 |
|    99 |
|    99 |
|    99 |
|   100 |
|   100 |
|    88 |
|    88 |
+-------+
11 rows in set (0.00 sec)

以下是显示组中具有最大计数值并带有其他列的记录的查询。这里，我们在一列中有重复的值，并且我们正在对这些值进行排序。在 ORDER BY DESC 之后，我们获取第一个值，并将其计数显示在新列“NumberOfCount”中 -

mysql> select Value,count(*) as NumberOfCount
   from DemoTable
   group by Value
   having count(*)=(select count(*) as NumberOfCount
      from DemoTable
      group by Value
      order by NumberOfCount desc
      limit 1);

这将产生以下输出 -

+-------+---------------+
| Value | NumberOfCount |
+-------+---------------+
|    88 |             5 |
+-------+---------------+
1 row in set (0.00 sec)

更新于: 2019 年 10 月 4 日

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