MySQL 查询如何在 SELECT 语句中生成行索引(排名)?


要生成行索引,请使用 ROW_NUMBER()。让我们首先创建一个表 -

mysql> create table DemoTable
(
   Name varchar(40)
);
Query OK, 0 rows affected (0.49 sec)

使用 insert 命令在表中插入一些记录 -

mysql> insert into DemoTable values('Chris');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable values('Chris');
Query OK, 1 row affected (0.22 sec)
mysql> insert into DemoTable values('Chris');
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable values('Robert');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable values('Robert');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable values('Adam');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable values('Adam');
Query OK, 1 row affected (0.22 sec)
mysql> insert into DemoTable values('Adam');
Query OK, 1 row affected (0.08 sec)
mysql> insert into DemoTable values('Adam');
Query OK, 1 row affected (0.08 sec)

使用 select 语句显示表中的所有记录 -

mysql> select *from DemoTable;

这会产生以下输出 -

+--------+
| Name   |
+--------+
| Chris  |
| Chris  |
| Chris  |
| Robert |
| Robert |
| Adam   |
| Adam   |
| Adam   |
| Adam   |
+--------+
9 rows in set (0.00 sec)

以下是 MySQL SELECT 语句中生成行索引的查询。在此,我们设置了重复姓名的排名 -

mysql> select Name,
row_number() over (partition by Name) as `Rank`
from DemoTable;

这会产生以下输出 -

+--------+------+
| Name   | Rank |
+--------+------+
| Adam   | 1    |
| Adam   | 2    |
| Adam   | 3    |
| Adam   | 4    |
| Chris  | 1    |
| Chris  | 2    |
| Chris  | 3    |
| Robert | 1    |
| Robert | 2    |
+--------+------+
9 rows in set (0.00 sec)

更新于: 06-Jul-2020

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