按订单日期记录,从 MySQL 中提取第 2 个已订购记录


要进行排序,请使用 ORDER BY 并且仅提取第 2 个已排序的记录,请使用 MySQL LIMIT 并设置偏移量。让我们首先创建一个 −

mysql> create table DemoTable1417
   -> (
   -> CustomerId int NOT NULL AUTO_INCREMENT PRIMARY KEY,
   -> CustomerName varchar(20),
   -> ShippingDate date
   -> );
Query OK, 0 rows affected (1.10 sec)

使用 insert 在表中插入一些记录 −

mysql> insert into DemoTable1417(CustomerName,ShippingDate) values('Chris','2019-01-21');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable1417(CustomerName,ShippingDate) values('David','2018-12-01');
Query OK, 1 row affected (0.55 sec)
mysql> insert into DemoTable1417(CustomerName,ShippingDate) values('Carol','2019-09-28');
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable1417(CustomerName,ShippingDate) values('Sam','2019-08-29');
Query OK, 1 row affected (0.17 sec)

使用 select 从表中显示所有记录 −

mysql> select * from DemoTable1417;

这将产生以下输出 −

+------------+--------------+--------------+
| CustomerId | CustomerName | ShippingDate |
+------------+--------------+--------------+
|          1 | Chris        | 2019-01-21   |
|          2 | David        | 2018-12-01   |
|          3 | Carol        | 2019-09-28   |
|          4 | Sam          | 2019-08-29   |
+------------+--------------+--------------+
4 rows in set (0.00 sec)

以下是对第 2 个已排序记录进行提取的查询 −

mysql> select CustomerName,ShippingDate from DemoTable1417 order by CustomerId limit 2,1;

这将产生以下输出 −

+--------------+--------------+
| CustomerName | ShippingDate |
+--------------+--------------+
| Carol        | 2019-09-28   |
+--------------+--------------+
1 row in set (0.00 sec)

更新日期: 12-11-2019

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