按订单日期记录,从 MySQL 中提取第 2 个已订购记录
要进行排序,请使用 ORDER BY 并且仅提取第 2 个已排序的记录,请使用 MySQL LIMIT 并设置偏移量。让我们首先创建一个 −
mysql> create table DemoTable1417 -> ( -> CustomerId int NOT NULL AUTO_INCREMENT PRIMARY KEY, -> CustomerName varchar(20), -> ShippingDate date -> ); Query OK, 0 rows affected (1.10 sec)
使用 insert 在表中插入一些记录 −
mysql> insert into DemoTable1417(CustomerName,ShippingDate) values('Chris','2019-01-21');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable1417(CustomerName,ShippingDate) values('David','2018-12-01');
Query OK, 1 row affected (0.55 sec)
mysql> insert into DemoTable1417(CustomerName,ShippingDate) values('Carol','2019-09-28');
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable1417(CustomerName,ShippingDate) values('Sam','2019-08-29');
Query OK, 1 row affected (0.17 sec)使用 select 从表中显示所有记录 −
mysql> select * from DemoTable1417;
这将产生以下输出 −
+------------+--------------+--------------+ | CustomerId | CustomerName | ShippingDate | +------------+--------------+--------------+ | 1 | Chris | 2019-01-21 | | 2 | David | 2018-12-01 | | 3 | Carol | 2019-09-28 | | 4 | Sam | 2019-08-29 | +------------+--------------+--------------+ 4 rows in set (0.00 sec)
以下是对第 2 个已排序记录进行提取的查询 −
mysql> select CustomerName,ShippingDate from DemoTable1417 order by CustomerId limit 2,1;
这将产生以下输出 −
+--------------+--------------+ | CustomerName | ShippingDate | +--------------+--------------+ | Carol | 2019-09-28 | +--------------+--------------+ 1 row in set (0.00 sec)
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