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法律学Python Pandas——从 TimeDeltaIndex 提取每个元素的秒数
要从 TimeDeltaIndex 对象中提取每个元素的秒数，请使用 TimedeltaIndex.seconds 属性
首先，导入所需的库 −
import pandas as pd
创建一个 TimeDeltaIndex 对象。我们已经使用 'data' 参数设置了类似时间增量的数据 −
tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min 35s 3us 10ns', '+22:39:19.999999', '2 day 4h 03:08:02.000045', '+21:15:45.999999'])
显示 TimedeltaIndex −
print("TimedeltaIndex...\n", tdIndex)从 TimeDeltaIndex 的每个元素中显示秒数 −
print("\nThe number of seconds from the TimeDeltaIndex object...\n", tdIndex.seconds)示例
以下为代码 −
import pandas as pd
# Create a TimeDeltaIndex object
# We have set the timedelta-like data using the 'data' parameter as well
tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min 35s 3us 10ns', '+22:39:19.999999',
'2 day 4h 03:08:02.000045', '+21:15:45.999999'])
# display TimedeltaIndex
print("TimedeltaIndex...\n", tdIndex)
# display the number of seconds from each element of TimeDeltaIndex
print("\nThe number of seconds from the TimeDeltaIndex object...\n", tdIndex.seconds)
# Return a dataframe of the components of TimeDeltas
print("\nThe Dataframe of the components of TimeDeltas...\n", tdIndex.components)输出
这将生成以下代码 −
TimedeltaIndex... TimedeltaIndex(['10 days 05:02:35.000003010', '0 days 22:39:19.999999', '2 days 07:08:02.000045', '0 days 21:15:45.999999'], dtype='timedelta64[ns]', freq=None) The number of seconds from the TimeDeltaIndex object... Int64Index([18155, 81559, 25682, 76545], dtype='int64') The Dataframe of the components of TimeDeltas... days hours minutes seconds milliseconds microseconds nanoseconds 0 10 5 2 35 0 3 10 1 0 22 39 19 999 999 0 2 2 7 8 2 0 45 0 3 0 21 15 45 999 999 0
更新于： 19-10-2021
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