从 C# 中的 HybridDictionary 中删除所有条目
要从 HybridDictionary 中删除所有条目,代码如下 −
示例
using System; using System.Collections; using System.Collections.Specialized; public class Demo { public static void Main(){ HybridDictionary dict1 = new HybridDictionary(); dict1.Add("A", "Books"); dict1.Add("B", "Electronics"); dict1.Add("C", "Smart Wearables"); dict1.Add("D", "Pet Supplies"); dict1.Add("E", "Clothing"); dict1.Add("F", "Footwear"); Console.WriteLine("HybridDictionary1 elements..."); foreach(DictionaryEntry d in dict1){ Console.WriteLine(d.Key + " " + d.Value); } Console.WriteLine("Count of Key/value pairs in Dictionary1 = "+dict1.Count); HybridDictionary dict2 = new HybridDictionary(); dict2.Add("1", "One"); dict2.Add("2", "Two"); dict2.Add("3", "Three"); dict2.Add("4", "Four"); dict2.Add("5", "Five"); dict2.Add("6", "Six"); Console.WriteLine("
HybridDictionary2 elements..."); foreach(DictionaryEntry d in dict2){ Console.WriteLine(d.Key + " " + d.Value); } Console.WriteLine("Count of Key/value pairs in Dictionary2 = "+dict1.Count); dict2.Clear(); Console.WriteLine("Count of Key/value pairs in Dictionary2 (Updated) = "+dict2.Count); } }
输出
这将生成以下输出 −
HybridDictionary1 elements... A Books B Electronics C Smart Wearables D Pet Supplies E Clothing F Footwear Count of Key/value pairs in Dictionary1 = 6 HybridDictionary2 elements... 1 One 2 Two 3 Three 4 Four 5 Five 6 Six Count of Key/value pairs in Dictionary2 = 6 Count of Key/value pairs in Dictionary2 (Updated) = 0
示例
我们来看另一个示例 −
using System; using System.Collections; using System.Collections.Specialized; public class Demo { public static void Main(){ HybridDictionary dict = new HybridDictionary(); dict.Add("One", "Accessories"); dict.Add("Two", "Pet Supplies"); Console.WriteLine("HybridDictionary elements..."); foreach(DictionaryEntry d in dict){ Console.WriteLine(d.Key + " " + d.Value); } Console.WriteLine("Count of Key/value pairs in Dictionary = "+dict.Count); } }
输出
这将生成以下输出 −
HybridDictionary elements... One Accessories Two Pet Supplies Count of Key/value pairs in Dictionary = 2
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