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法律研究删除 C# 中 LinkedList 起始处的节点
以下为删除 LinkedList 起始处节点的代码 −
示例
using System;
using System.Collections.Generic;
public class Demo {
public static void Main(){
LinkedList<string> list = new LinkedList<string>();
list.AddLast("One");
list.AddLast("Two");
list.AddLast("Three");
list.AddLast("Three");
list.AddLast("Three");
list.AddLast("Four");
Console.WriteLine("Count of nodes = " + list.Count);
Console.WriteLine("Elements in LinkedList... (Enumerator iterating through LinkedList)");
LinkedList<string>.Enumerator demoEnum = list.GetEnumerator();
while (demoEnum.MoveNext()) {
string res = demoEnum.Current;
Console.WriteLine(res);
}
list.RemoveFirst();
Console.WriteLine("Count of nodes (UPDATED) = " + list.Count);
Console.WriteLine("Elements in LinkedList... (Enumerator iterating through LinkedList)..UPDATED");
demoEnum = list.GetEnumerator();
while (demoEnum.MoveNext()) {
string res = demoEnum.Current;
Console.WriteLine(res);
}
}
}输出
以下为输出内容 −
Count of nodes = 6 Elements in LinkedList... (Enumerator iterating through LinkedList) One Two Three Three Three Four Count of nodes (UPDATED) = 5 Elements in LinkedList... (Enumerator iterating through LinkedList)..UPDATED Two Three Three Three Four
示例
我们来看另一个示例 −
using System;
using System.Collections.Generic;
public class Demo {
public static void Main(){
LinkedList<string> list = new LinkedList<string>();
list.AddLast("One");
list.AddLast("Two");
list.AddLast("Three");
list.AddLast("Three");
list.AddLast("Three");
list.AddLast("Four");
Console.WriteLine("Count of nodes = " + list.Count);
Console.WriteLine("Elements in LinkedList... (Enumerator iterating through LinkedList)");
LinkedList<string>.Enumerator demoEnum = list.GetEnumerator();
while (demoEnum.MoveNext()) {
string res = demoEnum.Current;
Console.WriteLine(res);
}
list.RemoveFirst();
Console.WriteLine("Count of nodes (UPDATED) = " + list.Count);
Console.WriteLine("Elements in LinkedList... (Enumerator iterating through LinkedList)..UPDATED");
demoEnum = list.GetEnumerator();
while (demoEnum.MoveNext()) {
string res = demoEnum.Current;
Console.WriteLine(res);
}
list.RemoveFirst();
Console.WriteLine("Count of nodes (UPDATED AGAIN) = " + list.Count);
Console.WriteLine("Elements in LinkedList... (Enumerator iterating through LinkedList)..UPDATED AGAIN");
demoEnum = list.GetEnumerator();
while (demoEnum.MoveNext()) {
string res = demoEnum.Current;
Console.WriteLine(res);
}
}
}输出
以下为输出内容 −
Count of nodes = 6 Elements in LinkedList... (Enumerator iterating through LinkedList) One Two Three Three Three Four Count of nodes (UPDATED) = 5 Elements in LinkedList... (Enumerator iterating through LinkedList)..UPDATED Two Three Three Three Four Count of nodes (UPDATED AGAIN) = 4 Elements in LinkedList... (Enumerator iterating through LinkedList)..UPDATED AGAIN Three Three Three Four
更新于：2020 年 5 月 2 日
67 次浏览
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