根据 JavaScript 中单词数组替换句子中特定单词的所有出现次数

我们需要编写一个 JavaScript 函数，它接收一个字符串和一个字符串数组。

我们的函数应当返回一个新字符串，其中字符串中数组中出现的单词的所有出现均被替换为空格。

我们的函数应当使用 `String.prototype.replace()` 方法来解决此问题。

示例

代码如下所示：

var excludeWords = ["A", "ABOUT", "ABOVE", "ACROSS", "ALL", "ALONG", "AM",
"AN", "AND", "ANY", "ASK", "AT", "AWAY", "CAN", "DID", "DIDN'T", "DO",
"DON'T", "FOR", "FROM", "HAD", "HAS", "HER", "HIS", "IN", "INTO", "IS",
"IT", "NONE", "NOT", "OF", "ON", "One", "OUT", "SO", "SOME", "THAT",
"THE", "THEIR", "THERE", "THEY", "THESE", "THIS", "TO", "TWIT", "WAS",
"WERE", "WEREN'T", "WHICH", "WILL", "WITH", "WHAT", "WHEN", "WHY"];
var sentence = "The first solution does not work for any UTF-8 alphaben. I
have managed to create function which do not use RegExp and use good UTF-8
support in JavaScript engine. The idea is simple if symbol is equal in
uppercase and lowercase it is special character. The only exception is
made for whitespace.";
const removeExcludedWords = (str, words) => {
   let sentence = '';
   const regex = new RegExp(`\b(${words.join('|')})\b`, 'gi');
   sentence = str.replace(regex, "");
   return sentence;
};
console.log(removeExcludedWords(sentence, excludeWords));

输出

控制台中输出：

first solution does work UTF-8 alphaben. I have managed create
function use RegExp use good UTF-8 support JavaScript
engine. idea simple if symbol equal uppercase lowercase special
character. only exception made whitespace.

更新于：12-Oct-2020

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