我们可以在 JavaScript 中重新抛出错误吗？解释一下。

在捕获异常后，可以使用 throw 重新抛出该异常。

以下是 JavaScript 中重新抛出错误的代码 −

示例

<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8" />
<meta name="viewport" content="width=device-width, initial-scale=1.0" />
<title>Document</title>
<style>
   body {
      font-family: "Segoe UI", Tahoma, Geneva, Verdana, sans-serif;
   }
   .result {
      font-size: 18px;
      font-weight: 500;
      color: rebeccapurple;
   }
</style>
</head>
<body>
<h1>Re-throw errors in JavaScript</h1>
<input type="number" class="num" />
<button class="Btn">CHECK</button>
<div class="result"></div>
<h3>
Enter a number bigger than 40 to re throw error;
</h3>
<script>
   let BtnEle = document.querySelector(".Btn");
   let resEle = document.querySelector(".result");
   BtnEle.addEventListener("click", () => {
      let a = document.querySelector(".num").value;
      try {
         throw a;
      }
      catch (err) {
         resEle.innerHTML = "Error thrown = " + err + "<br>";
      if (a < 40) {
         resEle.innerHTML += "Error handled : Value less than 40";
      } else {
         resEle.innerHTML += "Value more than 40 rethrowing error";
         throw err;
      }
   }
});
</script>
</body>
</html>