在 MySQL 中删除带 tablename.columnname = value 的记录
要以所需方式删除记录,语法如下 −
delete from yourTableName where yourTableName .yourColumnName=yourValue;
让我们首先创建一个表 −
mysql> create table DemoTable ( StudentName varchar(100), StudentAge int ); Query OK, 0 rows affected (0.81 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable values('Chris',21); Query OK, 1 row affected (0.15 sec) mysql> insert into DemoTable values('Robert',20); Query OK, 1 row affected (0.12 sec) mysql> insert into DemoTable values('David',22); Query OK, 1 row affected (0.14 sec) mysql> insert into DemoTable values('Mike',24); Query OK, 1 row affected (0.16 sec) mysql> insert into DemoTable values('Sam',19); Query OK, 1 row affected (0.12 sec)
使用 select 语句显示表中的所有记录 −
mysql> select *from DemoTable;
这将产生以下输出 −
+-------------+------------+ | StudentName | StudentAge | +-------------+------------+ | Chris | 21 | | Robert | 20 | | David | 22 | | Mike | 24 | | Sam | 19 | +-------------+------------+ 5 rows in set (0.00 sec)
以下是如何使用 tablename.columnname = value 来获取值并将其删除在 MySQL 中 −
mysql> delete from DemoTable where DemoTable.StudentName='Robert'; Query OK, 1 row affected (0.12 sec)
让我们再次检查表格记录 −
mysql> select *from DemoTable;
这将产生以下输出 −
+-------------+------------+ | StudentName | StudentAge | +-------------+------------+ | Chris | 21 | | David | 22 | | Mike | 24 | | Sam | 19 | +-------------+------------+ 4 rows in set (0.00 sec)
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