在 MySQL 中删除带 tablename.columnname = value 的记录


要以所需方式删除记录,语法如下 −

delete from yourTableName where yourTableName .yourColumnName=yourValue;

让我们首先创建一个表 −

mysql> create table DemoTable
(
   StudentName varchar(100),
   StudentAge int
);
Query OK, 0 rows affected (0.81 sec)

使用 insert 命令在表中插入一些记录 −

mysql> insert into DemoTable values('Chris',21);
Query OK, 1 row affected (0.15 sec)
mysql> insert into DemoTable values('Robert',20);
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable values('David',22);
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable values('Mike',24);
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable values('Sam',19);
Query OK, 1 row affected (0.12 sec)

使用 select 语句显示表中的所有记录 −

mysql> select *from DemoTable;

这将产生以下输出 −

+-------------+------------+
| StudentName | StudentAge |
+-------------+------------+
| Chris       |         21 |
| Robert      |         20 |
| David       |         22 |
| Mike        |         24 |
| Sam         |         19 |
+-------------+------------+
5 rows in set (0.00 sec)

以下是如何使用 tablename.columnname = value 来获取值并将其删除在 MySQL 中 −

mysql> delete from DemoTable where DemoTable.StudentName='Robert';
Query OK, 1 row affected (0.12 sec)

让我们再次检查表格记录 −

mysql> select *from DemoTable;

这将产生以下输出 −

+-------------+------------+
| StudentName | StudentAge |
+-------------+------------+
| Chris       |         21 |
| David       |         22 |
| Mike        |         24 |
| Sam         |         19 |
+-------------+------------+
4 rows in set (0.00 sec)

更新于: 2019-09-24

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