如何在MySQL中仅从一个表中选择数据,其中该表中的列值与另一个表中的列值匹配?
为此,您可以使用子查询以及EXISTS。让我们首先创建一个表:
mysql> create table DemoTable1 -> ( -> Id int, -> SubjectName varchar(20) -> ); Query OK, 0 rows affected (0.58 sec)
使用insert命令在表中插入一些记录:
mysql> insert into DemoTable1 values(111,'MySQL'); Query OK, 1 row affected (0.12 sec) mysql> insert into DemoTable1 values(112,'MongoDB'); Query OK, 1 row affected (0.15 sec) mysql> insert into DemoTable1 values(113,'Java'); Query OK, 1 row affected (0.17 sec) mysql> insert into DemoTable1 values(114,'C'); Query OK, 1 row affected (0.27 sec) mysql> insert into DemoTable1 values(115,'MySQL'); Query OK, 1 row affected (0.23 sec)
使用select语句显示表中的所有记录:
mysql> select * from DemoTable1;
这将产生以下输出:
+------+-------------+ | Id | SubjectName | +------+-------------+ | 111 | MySQL | | 112 | MongoDB | | 113 | Java | | 114 | C | | 115 | MySQL | +------+-------------+ 5 rows in set (0.00 sec)
以下是创建第二个表的查询:
mysql> create table DemoTable2 -> ( -> FirstName varchar(20), -> StudentSubject varchar(20) -> ); Query OK, 0 rows affected (0.73 sec)
使用insert命令在表中插入一些记录:
mysql> insert into DemoTable2 values('Chris','MySQL');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable2 values('Bob','MySQL');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable2 values('Sam','MySQL');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable2 values('Carol','C');
Query OK, 1 row affected (0.19 sec)使用select语句显示表中的所有记录:
mysql> select * from DemoTable2;
这将产生以下输出:
+-----------+----------------+ | FirstName | StudentSubject | +-----------+----------------+ | Chris | MySQL | | Bob | MySQL | | Sam | MySQL | | Carol | C | +-----------+----------------+ 4 rows in set (0.00 sec)
以下是仅从一个表中选择数据,其中该表中的列值与另一个表中的列值匹配的查询:
mysql> select Id from DemoTable1 -> where exists -> ( -> select 1 from DemoTable2 -> where SubjectName=StudentSubject -> );
这将产生以下输出:
+------+ | Id | +------+ | 111 | | 114 | | 115 | +------+ 3 rows in set (0.00 sec)
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