如何利用 MySQL 辨识所有数据表中存在的栏位?


如要辨识栏位名称,请在 MySQL 中使用 INFORMATION_SCHEMA.COLUMNS。以下是语法 −

select table_name,column_name
from INFORMATION_SCHEMA.COLUMNS
where table_schema = SCHEMA()
andcolumn_name='anyColumnName';

让我们执行上述查询,以辨识所有数据表中存在的栏位。此处,我们正在查找 EmployeeAge 栏位是否存在 −

mysql> select table_name,column_name
   FROM INFORMATION_SCHEMA.COLUMNS
   WHERE table_schema = SCHEMA()
   AND column_name='EmployeeAge';

这将产生以下输出,其中包含带有特定列“EmployeeAge”的数据表 −

+---------------+-------------+
| TABLE_NAME    | COLUMN_NAME |
+---------------+-------------+
| demotable1153 | EmployeeAge |
| demotable1297 | EmployeeAge |
| demotable1303 | EmployeeAge |
| demotable1328 | EmployeeAge |
| demotable1378 | EmployeeAge |
| demotable1530 | EmployeeAge |
| demotable1559 | EmployeeAge |
| demotable1586 | EmployeeAge |
| demotable1798 | EmployeeAge |
| demotable1901 | EmployeeAge |
| demotable511  | EmployeeAge |
| demotable912  | EmployeeAge |
+---------------+-------------+
12 rows in set (0.00 sec)

为了证明此点,让我们检查上述任一数据表的说明 −

mysql> desc demotable1153;

这将产生以下输出,其中包含 demotable1153 中 EmployeeAge 栏位的存在 −

+--------------+-------------+------+-----+---------+----------------+
| Field        | Type        | Null | Key | Default | Extra          |
+--------------+-------------+------+-----+---------+----------------+
| EmployeeId   | int(11)     | NO   | PRI | NULL    | auto_increment |
| EmployeeName | varchar(40) | YES  | MUL | NULL    |                |
| EmployeeAge  | int(11)     | YES  |     | NULL    |                |
+--------------+-------------+------+-----+---------+----------------+
3 rows in set (0.00 sec)

更新于: 2019 年 12 月 31 日

112 次浏览

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