如何利用 MySQL 辨识所有数据表中存在的栏位?
如要辨识栏位名称,请在 MySQL 中使用 INFORMATION_SCHEMA.COLUMNS。以下是语法 −
select table_name,column_name from INFORMATION_SCHEMA.COLUMNS where table_schema = SCHEMA() andcolumn_name='anyColumnName';
让我们执行上述查询,以辨识所有数据表中存在的栏位。此处,我们正在查找 EmployeeAge 栏位是否存在 −
mysql> select table_name,column_name FROM INFORMATION_SCHEMA.COLUMNS WHERE table_schema = SCHEMA() AND column_name='EmployeeAge';
这将产生以下输出,其中包含带有特定列“EmployeeAge”的数据表 −
+---------------+-------------+ | TABLE_NAME | COLUMN_NAME | +---------------+-------------+ | demotable1153 | EmployeeAge | | demotable1297 | EmployeeAge | | demotable1303 | EmployeeAge | | demotable1328 | EmployeeAge | | demotable1378 | EmployeeAge | | demotable1530 | EmployeeAge | | demotable1559 | EmployeeAge | | demotable1586 | EmployeeAge | | demotable1798 | EmployeeAge | | demotable1901 | EmployeeAge | | demotable511 | EmployeeAge | | demotable912 | EmployeeAge | +---------------+-------------+ 12 rows in set (0.00 sec)
为了证明此点,让我们检查上述任一数据表的说明 −
mysql> desc demotable1153;
这将产生以下输出,其中包含 demotable1153 中 EmployeeAge 栏位的存在 −
+--------------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +--------------+-------------+------+-----+---------+----------------+ | EmployeeId | int(11) | NO | PRI | NULL | auto_increment | | EmployeeName | varchar(40) | YES | MUL | NULL | | | EmployeeAge | int(11) | YES | | NULL | | +--------------+-------------+------+-----+---------+----------------+ 3 rows in set (0.00 sec)
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