如何使用 MySQL LIKE 创建搜索系统,并根据关键字显示结果?
要根据关键字显示结果,请使用 LIKE 运算符,语法如下 −
select *from yourTableName where yourColumnName LIKE '%yourValue%';
我们首先创建一个表 −
mysql> create table DemoTable812(Comments text); Query OK, 0 rows affected (0.61 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable812 values('Good Looking'); Query OK, 1 row affected (0.19 sec) mysql> insert into DemoTable812 values('Awesome'); Query OK, 1 row affected (0.18 sec) mysql> insert into DemoTable812 values('Looking Gorgeous'); Query OK, 1 row affected (0.09 sec) mysql> insert into DemoTable812 values('Good Luck'); Query OK, 1 row affected (0.20 sec) mysql> insert into DemoTable812 values('Have a nice day'); Query OK, 1 row affected (0.21 sec)
使用 select 语句显示表中的所有记录 −
mysql> select *from DemoTable812;
这将产生以下输出 −
+------------------+ | Comments | +------------------+ | Good Looking | | Awesome | | Looking Gorgeous | | Good Luck | | Have a nice day | +------------------+ 5 rows in set (0.00 sec)
以下查询使用 MySQL LIKE 创建搜索系统,并根据关键字显示结果 −
mysql> select *from DemoTable812 where Comments LIKE '%Look%';
这将产生以下输出 −
+------------------+ | Comments | +------------------+ | Good Looking | | Looking Gorgeous | +------------------+ 2 rows in set (0.00 sec)
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