在 MongoDB 中,使用 $in 搜索比执行多次单一搜索更快吗?
是的,使用 $in 更快。我们看一个示例并创建一个包含文档的集合 -
> db.demo653.insertOne({subject:"MySQL"}); { "acknowledged" : true, "insertedId" : ObjectId("5ea04b274deddd72997713c0") } > db.demo653.insertOne({subject:"MongoDB"}); { "acknowledged" : true, "insertedId" : ObjectId("5ea04b304deddd72997713c1") } > db.demo653.insertOne({subject:"Java"}); { "acknowledged" : true, "insertedId" : ObjectId("5ea04b354deddd72997713c2") } > db.demo653.insertOne({subject:"C"}); { "acknowledged" : true, "insertedId" : ObjectId("5ea04b384deddd72997713c3") } > db.demo653.insertOne({subject:"C++"}); { "acknowledged" : true, "insertedId" : ObjectId("5ea04b3b4deddd72997713c4") }
使用 find() 方法从集合中显示所有文档 -
> db.demo653.find();
这将产生以下输出 -
{ "_id" : ObjectId("5ea04b274deddd72997713c0"), "subject" : "MySQL" } { "_id" : ObjectId("5ea04b304deddd72997713c1"), "subject" : "MongoDB" } { "_id" : ObjectId("5ea04b354deddd72997713c2"), "subject" : "Java" } { "_id" : ObjectId("5ea04b384deddd72997713c3"), "subject" : "C" } { "_id" : ObjectId("5ea04b3b4deddd72997713c4"), "subject" : "C++" }
以下是使用 $in 并比执行多次单一搜索更快地进行搜索的查询 -
> db.demo653.find({subject:{$in:["MySQL","C++","C"]}});
这将产生以下输出 -
{ "_id" : ObjectId("5ea04b274deddd72997713c0"), "subject" : "MySQL" } { "_id" : ObjectId("5ea04b384deddd72997713c3"), "subject" : "C" } { "_id" : ObjectId("5ea04b3b4deddd72997713c4"), "subject" : "C++" }
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