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Java - String regionMatches() 方法
Java String regionMatches() 方法检查两个字符串区域是否等效。它将当前对象的子字符串与给定字符串的子字符串进行比较。
如果这些子字符串表示相同的字符序列,则此方法返回 true。此方法有两个多态变体。它们的语法如下所示,一个区分大小写,另一个忽略大小写。
语法
以下是Java String regionMatches() 方法的语法:
public boolean regionMatches(int toffset, String other, int ooffset, int len) // first syntax or, public boolean regionMatches(boolean ignoreCase, int toffset, String other, int ooffset, int len) // second syntax
参数
toffset − 此字符串中子区域的起始偏移量。
other − 字符串参数。
ooffset − 字符串参数中子区域的起始偏移量。
len − 要比较的字符数。
ignoreCase − 如果为 true,则在比较字符时忽略大小写。# 第二种语法
返回值
如果此字符串的指定子区域与字符串参数的指定子区域完全匹配,则此方法返回 true;否则返回 false。
检查字符串区域是否等效的示例
以下示例显示了 Java String regionMatches() 方法的使用方法。这里我们初始化两个 String 对象 str1 和 str2,并匹配字符串 "str1" 中索引 "14" 处的字符与字符串 "str2" 中索引 "22" 处的字符,同时考虑字母的大小写:
package com.tutorialspoint;
public class StringDemo {
public static void main(String[] args) {
String str1 = "Collection of tutorials";
String str2 = "Consists of different tutorials";
/* matches characters from index 14 in str1 to characters from
index 22 in str2 considering same case of the letters.*/
boolean match1 = str1.regionMatches(14, str2, 22, 9);
System.out.println("region matched = " + match1);
// considering different case, will return false
str2 = "Consists of different Tutorials";
match1 = str1.regionMatches(14, str2, 22, 9);
System.out.println("region matched = " + match1);
}
}
输出
如果编译并运行上述程序,它将产生以下结果:
region matched = true region matched = false
忽略大小写时检查字符串区域是否等效的示例
通过初始化 String 对象并匹配字符串 "str1" 中索引 "14" 处的字符与字符串 "str2" 中索引 "22" 处的字符,同时考虑字母的大小写,以下示例显示了如何使用 Java String regionMatches() 方法:
package com.tutorialspoint;
public class StringDemo {
public static void main(String[] args) {
String str1 = "Collection of tutorials";
String str2 = "Consists of different tutorials";
/* matches characters from index 14 in str1 to characters from
index 22 in str2 considering same case of the letters */
boolean match1 = str1.regionMatches(14, str2, 22, 9);
System.out.println("region matched = " + match1);
/* considering different case, "true" is set which will ignore
case when matched */
str2 = "Consists of different Tutorials";
match1 = str1.regionMatches(true, 14, str2, 22, 9);
System.out.println("region matched = " + match1);
}
}
输出
如果编译并运行上述程序,输出将如下所示:
region matched = true region matched = true
示例
下面是另一个 regionMatches() 方法的代码,其中取一个字符串 "Welcome to Tutorialspoint",并将其子字符串视为 "TUTORIALS" 和 "Tutorials"。s1 的索引大于字符串长度,s2 的索引在字符串长度内:
package com.tutorialspoint;
public class StringDemo {
public static void main(String args[]) {
String s1 = new String("Welcome to Tutorialspoint");
String s2 = new String("TUTORIALS");
String s3 = new String("Tutorials");
System.out.print("Return Value :");
System.out.println(s1.regionMatches(50, s2, 0, 9));
System.out.print("Return Value :");
System.out.println(s1.regionMatches(11, s3, 0, 9));
}
}
输出
运行上述程序后,输出结果如下:
Return Value :false Return Value :true
使用负索引检查字符串区域是否等效的示例
在以下示例中,regionMatches() 方法用于查找给定两个字符串的子字符串或区域是否相等,同时传递负索引:
package com.tutorialspoint;
public class StringDemo {
public static void main(String args[]) {
String s1 = new String("Welcome to TutorixProject");
String s2 = new String("TUTORIX");
String s3 = new String("Tutorix");
System.out.print("Return Value :");
System.out.println(s1.regionMatches(-11, s2, 0, 9));
System.out.print("Return Value :");
System.out.println(s1.regionMatches(-11, s3, 0, 9));
}
}
输出
上述程序的输出如下:
Return Value :false Return Value :false