reluctant 量词 [X*?] 匹配

说明

Reluctant 量词 [X*?] 匹配存在的 X 为零或更多次。

示例

以下示例展示了 reluctant 量词的用法。

package com.tutorialspoint;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class ReluctantQuantifierDemo {
   private static final String REGEX = "T*?";
   private static final String INPUT = "abcdTatW";

   public static void main(String[] args) {
      // create a pattern
      Pattern  pattern = Pattern.compile(REGEX);
      
      // get a matcher object
      Matcher matcher = pattern.matcher(INPUT); 

      while(matcher.find()) {
         //Prints the start index of the match.
         System.out.println("Match String start(): "+matcher.start());
      }
   }
}

让我们编译并运行以上程序，这将产生以下结果 −

Match String start(): 0
Match String start(): 1
Match String start(): 2
Match String start(): 3
Match String start(): 4
Match String start(): 5
Match String start(): 6
Match String start(): 7
Match String start(): 8