C 语言阿姆斯壮数程序

阿姆斯壮数等于其各个数字的立方和。例如，153 是阿姆斯壮数，因为 -

153 = (1)3 + (5)3 + (3)3
153 = 1 + 125 + 27
153 = 153

算法

此程序的算法非常简单 -

START
   Step 1 → Take integer variable Arms
   Step 2 → Assign value to the variable
   Step 3 → Split all digits of Arms
   Step 4 → Find cube-value of each digits
   Step 5 → Add all cube-values together
   Step 6 → Save the output to Sum variable
   Step 7 → If Sum equals to Arms print Armstrong Number
   Step 8 → If Sum not equals to Arms print Not Armstrong Number
STOP

伪代码

我们可以草拟以上算法的伪代码，如下所示 -

procedure armstrong : number
   
   check = number
   rem   = 0
   
   WHILE check IS NOT 0
      rem ← check modulo 10
      sum ← sum + (rem)3
      divide check by 10
   END WHILE
      
   IF sum equals to number
      PRINT armstrong
   ELSE
      PRINT not an armstrong
   END IF

end procedure

实现

此算法的实现如下。你可以更改 arms 变量的值，然后执行和检查你的程序 -

#include <stdio.h>

int main() {
   int arms = 153; 
   int check, rem, sum = 0;

   check = arms;

   while(check != 0) {
      rem = check % 10;
      sum = sum + (rem * rem * rem);
      check = check / 10;
   }

   if(sum == arms) 
      printf("%d is an armstrong number.", arms);
   else 
      printf("%d is not an armstrong number.", arms);
      
   return 0;
}

输出

程序的输出应该是 -

153 is an armstrong number.