MySQL 从不同的起始值排序?


首先,让我们创建一个表 -

mysql> create table DemoTable
   (
   ClientId int NOT NULL AUTO_INCREMENT PRIMARY KEY,
   ClientName varchar(30)
   );
Query OK, 0 rows affected (0.74 sec)

使用 insert 命令在表中插入记录 -

mysql> insert into DemoTable(ClientName) values('John');
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable(ClientName) values('Chris');
Query OK, 1 row affected (0.17 sec)
mysql> insert into DemoTable(ClientName) values('Robert');
Query OK, 1 row affected (0.21 sec)
mysql> insert into DemoTable(ClientName) values('David');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable(ClientName) values('Bob');
Query OK, 1 row affected (0.15 sec)
mysql> insert into DemoTable(ClientName) values('Carol');
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable(ClientName) values('Sam');
Query OK, 1 row affected (0.11 sec)
mysql> insert into DemoTable(ClientName) values('Mike');
Query OK, 1 row affected (0.12 sec)

使用 select 语句从表中显示所有记录 -

mysql> select * from DemoTable;

这将生成以下输出 -

+----------+------------+
| ClientId | ClientName |
+----------+------------+
| 1        | John       |
| 2        | Chris      |
| 3        | Robert     |
| 4        | David      |
| 5        | Bob        |
| 6        | Carol      |
| 7        | Sam        |
| 8        | Mike       |
+----------+------------+
8 rows in set (0.00 sec)

以下是 MySQL 从某个起始值进行排序的查询 -

mysql> select *from DemoTable order by ClientId < 5,ClientId;

这将生成以下输出 -

+----------+------------+
| ClientId | ClientName |
+----------+------------+
| 5        | Bob        |
| 6        | Carol      |
| 7        | Sam        |
| 8        | Mike       |
| 1        | John       |
| 2        | Chris      |
| 3        | Robert     |
| 4        | David      |
+----------+------------+
8 rows in set (0.00 sec)

更新日期:2019-07-30

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