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法律研究Python Pandas - 从 IntervalIndex 获取中点
要从 IntervalIndex 获取中点，请在 Pandas 中使用 interval.mid 属性。首先，导入所需的库 −
import pandas as pd
创建 IntervalIndex −
interval = pd.IntervalIndex.from_arrays([10, 15, 20], [20, 25, 30])
显示间隔 −
print("IntervalIndex...\n",interval)返回间隔的中点 −
print("\nThe midpoint for the Interval...\n",interval.mid)
示例
以下为代码 −
import pandas as pd
# Create IntervalIndex
interval = pd.IntervalIndex.from_arrays([10, 15, 20], [20, 25, 30])
# Display the interval
print("IntervalIndex...\n",interval)
# Display the interval length
print("\nIntervalIndex length...\n",interval.length)
# Check whether the IntervalIndex is closed on the left-side, right-side, both or neither
print("\nChecking for the type of IntervalIndex...\n",interval.closed)
# the left bound
print("\nThe left bound for the IntervalIndex...\n",interval.left)
# the right bound
print("\nThe right bound for the IntervalIndex...\n",interval.right)
# return the midpoint of the Interval
print("\nThe midpoint for the Interval...\n",interval.mid)输出
这将产生以下输出 −
IntervalIndex... IntervalIndex([(10, 20], (15, 25], (20, 30]], dtype='interval[int64, right]') IntervalIndex length... Int64Index([10, 10, 10], dtype='int64') Checking for the type of IntervalIndex... right The left bound for the IntervalIndex... Int64Index([10, 15, 20], dtype='int64') The right bound for the IntervalIndex... Int64Index([20, 25, 30], dtype='int64') The midpoint for the Interval... Float64Index([15.0, 20.0, 25.0], dtype='float64')
更新于: 18-Oct-2021
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