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Legal StudiesPython 程序检查给定的字符串是否异构词
这里给定一个字符串，我们的任务是检查给定的字符串是否为异构词。
异构词检查的含义是，一个单词、短语或句子中没有一个字母出现超过一次。异构词可以与全异序词区分开来，后者使用所有字母表中的字母。
示例
字符串是 abc def ghi
This is Heterogram (no alphabet repeated)
字符串是 abc bcd dfh
This is not Heterogram. (b,c,d are repeated)
算法
Step 1: first we separate out list of all alphabets present in sentence. Step 2: Convert list of alphabets into set because set contains unique values. Step 3: if length of set is equal to number of alphabets that means each alphabet occurred once then sentence is heterogram, otherwise not.
示例代码
def stringheterogram(s, n):
hash = [0] * 26
for i in range(n):
if s[i] != ' ':
if hash[ord(s[i]) - ord('a')] == 0:
hash[ord(s[i]) - ord('a')] = 1
else:
return False
return True
# Driven Code
s = input("Enter the String ::>")
n = len(s)
print(s,"This string is Heterogram" if stringheterogram(s, n) else "This string is not Heterogram")输出
Enter the String ::> asd fgh jkl asd fgh jkl this string is Heterogram Enter the String ::>asdf asryy asdf asryy This string is not Heterogram
更新时间：2020 年 6 月 23 日
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