我们如何将子查询转换为 INNER JOIN?
为了让大家理解,我们使用以下表格中的数据 −
mysql> Select * from customers; +-------------+----------+ | Customer_Id | Name | +-------------+----------+ | 1 | Rahul | | 2 | Yashpal | | 3 | Gaurav | | 4 | Virender | +-------------+----------+ 4 rows in set (0.00 sec) mysql> Select * from reserve; +------+------------+ | ID | Day | +------+------------+ | 1 | 2017-12-30 | | 2 | 2017-12-28 | | 2 | 2017-12-25 | | 1 | 2017-12-24 | | 3 | 2017-12-26 | +------+------------+ 5 rows in set (0.00 sec)
现在,以下子查询将查找所有预留过汽车的客户的姓名。
mysql> Select Name from customers WHERE customer_id IN (Select id from reserve); +----------+ | Name | +----------+ | Rahul | | Yashpal | | Gaurav | +----------+ 3 rows in set (0.00 sec)
现在,借助以下步骤,我们可以将上述子查询转换为 inner join −
将子查询中命名的“Reserve”表移动到 FROM 子句中。
WHERE 子句将 customer_id 列与子查询返回的 id 进行比较。
因此,将表达式转换为两个表的 id 列之间的显式直接比较。
mysql> SELECT Name from customers, reserve WHERE customer_id = id; +----------+ | Name | +----------+ | Rahul | | Yashpal | | Yashpal | | Rahul | | Gaurav | +----------+ 5 rows in set (0.00 sec)
正如我们所见,上述结果与子查询的结果完全不同,因此使用 DISTINCT 关键字以获得以下相同结果
mysql> SELECT DISTINCT name from customers,reserve WHERE customer_id = id; +----------+ | Name | +----------+ | Rahul | | Yashpal | | Gaurav | +----------+ 3 rows in set (0.03 sec)
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