在 Python 中用一个埃尔米特级数除以另一个级数


如要将一个埃尔米特级数除以另一个级数,请在 Python Numpy 中使用 polynomial.hermite.hermdiv() 方法。此方法返回一个埃尔米特级数系数数组,表示商和余数。返回两个埃尔米特级数 c1 / c2 的商和余数。参数是系数序列,从最低阶“项”到最高阶,例如 [1,2,3] 表示级数 P_0 + 2*P_1 + 3*P_2。参数 c1 和 c2 是埃尔米特级数系数的一维数组,按从低到高的顺序排列。

步骤

首先,导入所需的库 -

import numpy as np
from numpy.polynomial import hermite as H

创建埃尔米特级数系数的一维数组 -

c1 = np.array([53., 30., 52., 7., 6.])
c2 = np.array([1, 2, 3])

显示系数数组 -

print("Array1...\n",c1)
print("\nArray2...\n",c2)

显示数据类型 -

print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)

检查这两个数组的维度 -

print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)

检查这两个数组的形状 -

print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)

如要将一个埃尔米特级数除以另一个级数,请在 Python Numpy 中使用 polynomial.hermite.hermdiv() 方法 -

print("\nResult (division)....\n",H.hermdiv(c1, c2))

示例

import numpy as np
from numpy.polynomial import hermite as H

# Create 1-D arrays of Hermite series coefficients
c1 = np.array([53., 30., 52., 7., 6.])
c2 = np.array([1, 2, 3])

# Display the arrays of coefficients
print("Array1...\n",c1)
print("\nArray2...\n",c2)

# Display the datatype
print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)

# Check the Dimensions of both the arrays
print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)

# Check the Shape of both the arrays
print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)

# To divide one Hermite series by another, use the polynomial.hermite.hermdiv() method in Python Numpy
print("\nResult (division)....\n",H.hermdiv(c1, c2))

输出

Array1...
   [53. 30. 52. 7. 6.]

Array2...
   [1 2 3]

Array1 datatype...
float64

Array2 datatype...
int64

Dimensions of Array1...
1

Dimensions of Array2...
1

Shape of Array1...
(5,)

Shape of Array2...
(3,)

Result (division)....
   (array([0., 1., 2.]), array([1., 1.]))

更新于:2022-03-01

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