在Python中求Hermite级数的导数
在Python中,可以使用`hermite.hermder()`方法求Hermite级数的导数。第一个参数`c`是Hermite级数系数的数组。如果`c`是多维的,不同的轴对应于不同的变量,每个轴的次数由相应的索引给出。第二个参数`m`是被求导的次数,必须是非负数。(默认值:1)第三个参数`scl`是一个标量。每次求导都乘以`scl`。最终结果是乘以`scl**m`。这是用于线性变量变化。(默认值:1)。第四个参数`axis`是求导的轴。(默认值:0)。
步骤
首先,导入所需的库:
import numpy as np from numpy.polynomial import hermite as H
创建一个系数数组:
c = np.array([1,2,3,4])
显示数组:
print("Our Array...\n",c)
检查维度:
print("\nDimensions of our Array...\n",c.ndim)
获取数据类型:
print("\nDatatype of our Array object...\n",c.dtype)
获取形状:
print("\nShape of our Array object...\n",c.shape)
在Python中,可以使用`hermite.hermder()`方法求Hermite级数的导数:
print("\nResult...\n",H.hermder(c))
示例
import numpy as np from numpy.polynomial import hermite as H # Create an array of coefficients c = np.array([1,2,3,4]) # Display the array print("Our Array...\n",c) # Check the Dimensions print("\nDimensions of our Array...\n",c.ndim) # Get the Datatype print("\nDatatype of our Array object...\n",c.dtype) # Get the Shape print("\nShape of our Array object...\n",c.shape) # To differentiate a Hermite series, use the hermite.hermder() method in Python print("\nResult...\n",H.hermder(c))
输出
Our Array... [1 2 3 4] Dimensions of our Array... 1 Datatype of our Array object... int64 Shape of our Array object... (4,) Result... [ 4. 12. 24.]
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