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法律研究在 Python 中从另一个 Hermite 级数中减去一个 Hermite 级数
若要从另一个 Hermite 级数中减去一个 Hermite 级数，请在 Python Numpy 中使用 polynomials.hermite.hermsub() 方法。该方法返回表示它们的差的 Hermite 级数的数组。返回两个 Hermite 级数 c1 - c2 的差。系数序列从低阶项到高阶项，即 [1,2,3] 表示级数 P_0 + 2*P_1 + 3*P_2。参数 c1 和 c2 是从低到高排列的 Hermite 级数系数的 1 维数组。
步骤
首先，导入所需的库 −
import numpy as np from numpy.polynomial import hermite as H
创建 Hermite 级数系数的 1 维数组 −
c1 = np.array([1,2,3]) c2 = np.array([3,2,1])
显示系数数组 −
print("Array1...\n",c1) print("\nArray2...\n",c2)
显示数据类型 −
print("\nArray1 datatype...\n",c1.dtype) print("\nArray2 datatype...\n",c2.dtype)
检查两个数组的维度 −
print("\nDimensions of Array1...\n",c1.ndim) print("\nDimensions of Array2...\n",c2.ndim)
检查两个数组的形状 −
print("\nShape of Array1...\n",c1.shape) print("\nShape of Array2...\n",c2.shape)
若要从另一个 Hermite 级数中减去一个 Hermite 级数，请在 Python Numpy 中使用 polynomial.hermite.hermsub() 方法 −
print("\nResult (difference)....\n",H.hermsub(c1, c2))
示例
import numpy as np from numpy.polynomial import hermite as H # Create 1-D arrays of Hermite series coefficients c1 = np.array([1,2,3]) c2 = np.array([3,2,1]) # Display the arrays of coefficients print("Array1...\n",c1) print("\nArray2...\n",c2) # Display the datatype print("\nArray1 datatype...\n",c1.dtype) print("\nArray2 datatype...\n",c2.dtype) # Check the Dimensions of both the arrays print("\nDimensions of Array1...\n",c1.ndim) print("\nDimensions of Array2...\n",c2.ndim) # Check the Shape of both the arrays print("\nShape of Array1...\n",c1.shape) print("\nShape of Array2...\n",c2.shape) # To subtract one Hermite series to another, use the polynomial.hermite.hermsub() method in Python Numpy # The method returns an array representing the Hermite series of their difference. print("\nResult (difference)....\n",H.hermsub(c1, c2))
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输出
Array1... [1 2 3] Array2... [3 2 1] Array1 datatype... int64 Array2 datatype... int64 Dimensions of Array1... 1 Dimensions of Array2... 1 Shape of Array1... (3,) Shape of Array2... (3,) Result (difference).... [-2. 0. 2.]
更新于：2022-03-01
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