如何获取 MySQL 表格中包含员工薪酬记录的前 3 个薪酬？

为此，使用 LIMIT 和 OFFSET。我们首先创建一个表 -

mysql> create table DemoTable867(EmployeeSalary int);
Query OK, 0 rows affected (0.64 sec)

使用 insert 命令在表中插入一些记录 -

mysql> insert into DemoTable867 values(63737);
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable867 values(899833);
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable867 values(23644);
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable867 values(89393);
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable867 values(534333);
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable867 values(889322);
Query OK, 1 row affected (0.08 sec)

使用 select 语句显示表中的所有记录 -

mysql> select *from DemoTable867;

这将产生以下输出 -

+----------------+
| EmployeeSalary |
+----------------+
| 63737          |
| 899833         |
| 23644          |
| 89393          |
| 534333         |
| 889322         |
+----------------+
6 rows in set (0.00 sec)

这是获取第一个最高薪酬的查询 -

mysql> select distinct(EmployeeSalary) from DemoTable867 order by EmployeeSalary DESC LIMIT 1;

这将产生以下输出 -

+----------------+
| EmployeeSalary |
+----------------+
| 899833         |
+----------------+
1 row in set (0.02 sec)

这是获取第二个最高薪酬的查询 -

mysql> select distinct(EmployeeSalary) from DemoTable867 order by EmployeeSalary DESC LIMIT 1 OFFSET 1;

这将产生以下输出 -

+----------------+
| EmployeeSalary |
+----------------+
| 889322         |
+----------------+
1 row in set (0.00 sec)

以下是对第三个最高薪酬进行查询

mysql> select distinct(EmployeeSalary) from DemoTable867 order by EmployeeSalary DESC LIMIT 1 OFFSET 2;

这将产生以下输出 -

+----------------+
| EmployeeSalary |
+----------------+
| 534333         |
+----------------+
1 row in set (0.00 sec)

更新日期：2019-09-03

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