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法律研究C++ 中随机配对为最大权重配对的概率
给定两个不同的数组，任务是找到随机选择的配对为最大权重配对的概率。
一个配对将包含一个来自例如数组1的元素和另一个来自另一个数组例如数组2的元素。因此，程序必须找到包含第一个元素为数组1的最大元素和第二个元素为数组2的最大元素的配对的概率，从而形成最大权重配对。
输入
arr1[] = { 2, 23 }
arr2[] = { 10, 3, 8 }输出
probability of maximum pair : 0.166667
说明
set of pairs from both the arrays are -: {(2, 10), (2, 3), (2, 8), (23, 10), (23, 3), (23, 8)}
Maximum weighted pair from the given set is: (23, 8)
Probability is : 1 / 6 = 0.166667输入 -
arr1[] = { 4, 5, 6 }
arr2[] = { 6, 2, 6 }输出 -
probability of maximum pair : 0.222222
说明
set of pairs from both the arrays are -: {(4, 6), (4, 2), (4, 6), (5, 6), (5, 2), (5, 6), (6, 6), (6, 2), (6, 6)}
Maximum weighted pair from the given set is (6, 6) which is occurring twice.
Probability is : 2 / 9 = 0.2222方法
输入数组元素
找到两个数组中的最大元素并计算由此形成的最大权重配对的总数
通过将最大权重配对的总数除以集合中配对的总数来计算概率
打印计算出的概率
算法
Start
Step1→ declare function to calculate maximum weighted pair
double max_pair(int arr1[], int arr2[], int size_1, int size_2)
declare int max_pair1 = INT_MIN, count_1 = 0
Loop For int i = 0 and i < size_1 and i++
IF arr1[i] > max_pair1
Set max_pair1 = arr1[i]
Set count_1 = 1
End
Else IF arr1[i] = max_pair1
Set count_1++
End
End
Declare int max_pair2 = INT_MIN, count_2 = 0
Loop For int i = 0 and i < size_2 and i++
IF arr2[i] > max_pair2
Set max_pair2 = arr2[i]
Set count_2 = 1
End
Else IFarr2[i] = max_pair2
Set count_2++
End
End
return (double)(count_1 * count_2) / (size_1 * size_2)
Step 2→ In main()
Declare int arr1[] = { 2, 23 }
Declare int arr2[] = { 10, 3, 8 }
Calculate int size_1 = sizeof(arr1) / sizeof(arr1[0])
Calculate int size_2 = sizeof(arr2) / sizeof(arr2[0])
Call max_pair(arr1, arr2, size_1, size_2)
Stop示例
#include <bits/stdc++.h>
using namespace std;
// Function to return probability
double max_pair(int arr1[], int arr2[], int size_1, int size_2){
//pair from array 1
int max_pair1 = INT_MIN, count_1 = 0;
for (int i = 0; i < size_1; i++){
if (arr1[i] > max_pair1){
max_pair1 = arr1[i];
count_1 = 1;
}
else if (arr1[i] == max_pair1){
count_1++;
}
}
//pair from array 2
int max_pair2 = INT_MIN, count_2 = 0;
for (int i = 0; i < size_2; i++){
if (arr2[i] > max_pair2){
max_pair2 = arr2[i];
count_2 = 1;
}
else if (arr2[i] == max_pair2){
count_2++;
}
}
return (double)(count_1 * count_2) / (size_1 * size_2);
}
int main(){
int arr1[] = { 2, 23 };
int arr2[] = { 10, 3, 8 };
int size_1 = sizeof(arr1) / sizeof(arr1[0]);
int size_2 = sizeof(arr2) / sizeof(arr2[0]);
cout <<"probability of maximum pair in both the arrays are "<<max_pair(arr1, arr2, size_1, size_2);
return 0;
}输出
如果运行以上代码，它将生成以下输出 -
probability of maximum pair in both the arrays are 0.166667
更新于: 2020-08-13
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