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法律研究Python Pandas - 如何对具有秒频率的 DateTimeIndex 执行向下取整操作
要对具有秒频率的 DateTimeIndex 执行向下取整操作，请使用 **DateTimeIndex.floor()** 方法。对于秒频率，请使用 **freq** 参数，其值为 **‘S’**
首先，导入所需的库 -
import pandas as pd
创建一个周期为 7 且频率为 S（即秒）的 DatetimeIndex -
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')显示 DateTimeIndex -
print("DateTimeIndex...\n", datetimeindex)
对 DateTimeIndex 日期执行具有秒频率的向下取整操作。对于秒频率，我们使用了 'S' -
print("\nPerforming floor operation with seconds frequency...\n",
datetimeindex.floor(freq='S'))示例
以下是代码 -
import pandas as pd
# DatetimeIndex with period 7 and frequency as S i.e. seconds
# timezone is Australia/Adelaide
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')
# display DateTimeIndex
print("DateTimeIndex...\n", datetimeindex)
# display DateTimeIndex frequency
print("DateTimeIndex frequency...\n", datetimeindex.freq)
# getting the second
res = datetimeindex.second
# display only the second
print("\nThe seconds from DateTimeIndex...\n", res)
# Floor operation on DateTimeIndex date with seconds frequency
# For seconds frequency, we have used 'S'
print("\nPerforming floor operation with seconds frequency...\n",
datetimeindex.floor(freq='S'))输出
这将生成以下代码 -
DateTimeIndex... DatetimeIndex(['2021-10-18 07:20:32.261811624+10:30', '2021-10-18 07:21:12.261811624+10:30', '2021-10-18 07:21:52.261811624+10:30', '2021-10-18 07:22:32.261811624+10:30', '2021-10-18 07:23:12.261811624+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq='40S') DateTimeIndex frequency... <40 * Seconds> The seconds from DateTimeIndex... Int64Index([32, 12, 52, 32, 12], dtype='int64') Performing floor operation with seconds frequency... DatetimeIndex(['2021-10-18 07:20:32+10:30', '2021-10-18 07:21:12+10:30', '2021-10-18 07:21:52+10:30', '2021-10-18 07:22:32+10:30', '2021-10-18 07:23:12+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq=None)
更新于: 2021年10月19日
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