Python Pandas - 如何对具有分钟频率的 DateTimeIndex 执行向下取整操作


若要对具有分钟频率的 DateTimeIndex 执行向下取整操作,请使用 DateTimeIndex.floor() 方法。对于分钟频率,使用 freq 参数,其值设为 ‘T’

首先,导入所需的库 −

import pandas as pd

使用周期 7 和频率为 s(即秒)创建 DateTimeIndex −

datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')

显示 DateTimeIndex −

print("DateTimeIndex...\n", datetimeindex)

针对具有分钟频率的 DateTimeIndex 日期执行向下取整操作。对于分钟频率,我们使用了 'T' −

print("\nPerforming floor operation with minute frequency...\n",
datetimeindex.floor(freq='T'))

示例

以下为代码 −

import pandas as pd

# DatetimeIndex with period 7 and frequency as s i.e. seconds
# timezone is Australia/Adelaide
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')

# display DateTimeIndex
print("DateTimeIndex...\n", datetimeindex)

# display DateTimeIndex frequency
print("DateTimeIndex frequency...\n", datetimeindex.freq)

# getting the minute
res = datetimeindex.minute

# display only the minute
print("\nThe minute from DateTimeIndex...\n", res)

# Floor operation on DateTimeIndex date with minute frequency
# For minute frequency, we have used 'T'
print("\nPerforming floor operation with minute frequency...\n",
datetimeindex.floor(freq='T'))

输出

这将生成以下代码 −

DateTimeIndex...
DatetimeIndex(['2021-10-18 07:20:32.261811624+10:30',
'2021-10-18 07:21:12.261811624+10:30',
'2021-10-18 07:21:52.261811624+10:30',
'2021-10-18 07:22:32.261811624+10:30',
'2021-10-18 07:23:12.261811624+10:30'],
dtype='datetime64[ns, Australia/Adelaide]', freq='40S')
DateTimeIndex frequency...
<40 * Seconds>

The minute from DateTimeIndex...
Int64Index([20, 21, 21, 22, 23], dtype='int64')
Performing floor operation with minute frequency...
DatetimeIndex(['2021-10-18 07:20:00+10:30', '2021-10-18 07:21:00+10:30',
'2021-10-18 07:21:00+10:30', '2021-10-18 07:22:00+10:30',
'2021-10-18 07:23:00+10:30'],
dtype='datetime64[ns, Australia/Adelaide]', freq=None)

更新于: 2021 年 10 月 19 日

71 次浏览

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