Python Pandas - 如何对具有分钟频率的 DateTimeIndex 执行向上取整运算
要对具有分钟频率的 DateTimeIndex 执行向上取整运算,请使用 **DateTimeIndex.ceil()** 方法。对于分钟频率,请使用值为 **‘T’** 的 **freq** 参数。
首先,导入所需的库:
import pandas as pd
创建一个周期为 5 且频率为秒 (s) 的 DatetimeIndex:
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')显示 DateTimeIndex:
print("DateTimeIndex...\n", datetimeindex)
对 DateTimeIndex 日期执行以分钟为频率的向上取整运算。对于分钟频率,我们使用了 'T':
print("\nPerforming ceil operation with minute frequency...\n",
datetimeindex.ceil(freq='T'))示例
以下是代码:
import pandas as pd
# DatetimeIndex with period 5 and frequency as s i.e. seconds
# timezone is Australia/Adelaide
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')
# display DateTimeIndex
print("DateTimeIndex...\n", datetimeindex)
# display DateTimeIndex frequency
print("DateTimeIndex frequency...\n", datetimeindex.freq)
# getting the minute
res = datetimeindex.minute
# display only the minute
print("\nThe minute from DateTimeIndex...\n", res)
# ceil operation on DateTimeIndex date with minute frequency
# For minute frequency, we have used 'T'
print("\nPerforming ceil operation with minute frequency...\n",
datetimeindex.ceil(freq='T'))输出
这将产生以下代码:
DateTimeIndex... DatetimeIndex(['2021-10-18 07:20:32.261811624+10:30', '2021-10-18 07:21:12.261811624+10:30', '2021-10-18 07:21:52.261811624+10:30', '2021-10-18 07:22:32.261811624+10:30', '2021-10-18 07:23:12.261811624+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq='40S') DateTimeIndex frequency... <40 * Seconds> The minute from DateTimeIndex... Int64Index([20, 21, 21, 22, 23], dtype='int64') Performing ceil operation with minute frequency... DatetimeIndex(['2021-10-18 07:21:00+10:30', '2021-10-18 07:22:00+10:30', '2021-10-18 07:22:00+10:30', '2021-10-18 07:23:00+10:30', '2021-10-18 07:24:00+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq=None)
广告
数据结构
网络
关系数据库管理系统 (RDBMS)
操作系统
Java
iOS
HTML
CSS
Android
Python
C语言编程
C++
C#
MongoDB
MySQL
Javascript
PHP