检查句子是否为全套字母句的 Python 程序。


给定一个句子。我们的任务是检查这个句子是否为全套字母句。全套字母句的逻辑是,单词或句子至少包含字母表的每个字母一次。要解决这个问题,我们使用 set()方法和列表推导技术。

示例

Input: string = 'abc def ghi jkl mno pqr stu vwx yz'
Output: Yes
// contains all the characters from ‘a’ to ‘z’
Input: str='python program'
Output: No
// Does not contains all the characters from ‘a’ to 'z'

算法

Step 1: create a string.
Step 2: Convert the complete sentence to a lower case using lower () method.
Step 3: convert the input string into a set (), so that we will list of all unique characters present in the sentence.
Step 4: separate out all alphabets ord () returns ASCII value of the character.
Step 5: If length of list is 26 that means all characters are present and sentence is Pangram otherwise not.

示例代码

def checkPangram(s):
   lst = []
   for i in range(26):
      lst.append(False)
   for c in s.lower(): 
      if not c == " ":
         lst[ord(c) -ord('a')]=True
   for ch in lst:
      if ch == False:
         return False
   return True
# Driver Program 
str1=input("Enter The String ::7gt;")
if (checkPangram(str1)):
   print ('"'+str1+'"')
   print ("is a pangram")
else:
   print ('"'+str1+'"')
   print ("is not a pangram")

输出

Enter The String ::abc def ghi jkl mno pqr stu vwx yz
"abc def ghi jkl mno pqr stu vwx yz"
is a pangram
Enter The String ::> python program
"pyhton program"
is not a pangram

更新时间: 2019 年 7 月 30 日

332 次浏览

开启你的 事业

完成课程并获得认证

入门
广告